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A new weight-loss program claims that participants will lose an average of more than 10 pounds after completing it The accompanying data table snows the weights of eight individuals before and after the program. Complete parts (a) through (e) below. 1 Click the icon to view the data table. a. Perform a hypothesis test using a = 0.05 to determine if the average weight loss was more than 10 pounds for participants in the weight-loss program. Let Hg be the population mean of matched-pair differences for the weight before the program minus the weight after the program. State the null and alternative hypotheses. Choose the correct answer below. O A. Ho Hg s 10 H: Hg < 10 OC. Ho Hg < 10 H: Hg 2 10 OE. Ho Hgs 10 H, Hg> 10 OB. Ho Has 10 H: Hg# 10 O D. Ho Hg# 10 H Hg = 10 OF. Ho Ha = 10 H, H 10 b. Calculate the appropriate test statistic and interpret the results of the hypothesis test using a =0.05. The test statistic is (Round to two decimal places as needed.) The critical value(s) is(are) (Use a comma to separate answers as needed. Round to two decimal places as needed.) Interpret the results of the hypothesis test. Since the test statistic (1) the critical value(s). (2) the null hypothesis. There is (3). evidence that the mean score is lower after the weight-loss program. c. Identify the p-value and interpret the result. p-value = (Round to three decimal places as needed.) Interpret the result. Since the p-value (4) the significance level, (5). the null hypothesis. There is (6) evidence that the mean score is lower after the weight-loss program. d. Construct a 90% confidence interval to estimate the average weight loss for individuals in the program. Interpret the results. UCLa =

A new weight-loss program claims that participants will lose an average of more than 10 pounds after completing it The accompanying data table snows the weights of eight individuals before and after the program. Complete parts (a) through (e) below. 1 Click the icon to view the data table. a. Perform a hypothesis test using a = 0.05 to determine if the average weight loss was more than 10 pounds for participants in the weight-loss program. Let Hg be the population mean of matched-pair differences for the weight before the program minus the weight after the program. State the null and alternative hypotheses. Choose the correct answer below. O A. Ho Hg s 10 H: Hg < 10 OC. Ho Hg < 10 H: Hg 2 10 OE. Ho Hgs 10 H, Hg> 10 OB. Ho Has 10 H: Hg# 10 O D. Ho Hg# 10 H Hg = 10 OF. Ho Ha = 10 H, H 10 b. Calculate the appropriate test statistic and interpret the results of the hypothesis test using a =0.05. The test statistic is (Round to two decimal places as needed.) The critical value(s) is(are) (Use a comma to separate answers as needed. Round to two decimal places as needed.) Interpret the results of the hypothesis test. Since the test statistic (1) the critical value(s). (2) the null hypothesis. There is (3). evidence that the mean score is lower after the weight-loss program. c. Identify the p-value and interpret the result. p-value = (Round to three decimal places as needed.) Interpret the result. Since the p-value (4) the significance level, (5). the null hypothesis. There is (6) evidence that the mean score is lower after the weight-loss program. d. Construct a 90% confidence interval to estimate the average weight loss for individuals in the program. Interpret the results. UCLa =

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

THE DATA: 

Data: 

Person
Before
After
 
1
 
226
202
 
2
 
214
195
 
3
 
207
193
 
4
 
186
172
 
5
 
202
196
 
6
 
197
181
 
7
 
242
231
 
8
 
191
193
Interpret the results. Because 10 is (7) the interval, there (8) enough evidence that the average weight loss is more than 10 pounds for participants in the weight-loss program. e. What assumptions need to be made in order to perform this procedure? O A. The samples are independent, and the distribution of the matched-pair differences between the measurements for the population is approximately normal if the number of matched pairs is 30 or greater. O B. The samples are independent, and the distribution of the matched-pair differences between the measurements for the population is approximately uniform if the number of matched pairs is less than 30. OC. The samples are dependent, and the distribution of the matched-pair differences between the measurements for the population is approximately uniform if the number of matched pairs is 30 or greater. O D. The samples are dependent, and the distribution of the matched-pair differences between the measurements for the population is approximately normal if the number of matched pairs is less than 30. 1: Weights Person Before After 1 226 202 2 214 195 207 193 4 186 172 202 196 6 197 181 7 242 231 8 191 193 is greater than O falls between does not fall between O reject O do not reject O sufficient O insufficient O is greater than O is less than or equal to O reject O do not reject O below O within or above (1) (2) (3) (4) (5) (6) O insufficient (7) (8) O is O is not O sufficient is less than or equal to
Transcribed Image Text:Interpret the results. Because 10 is (7) the interval, there (8) enough evidence that the average weight loss is more than 10 pounds for participants in the weight-loss program. e. What assumptions need to be made in order to perform this procedure? O A. The samples are independent, and the distribution of the matched-pair differences between the measurements for the population is approximately normal if the number of matched pairs is 30 or greater. O B. The samples are independent, and the distribution of the matched-pair differences between the measurements for the population is approximately uniform if the number of matched pairs is less than 30. OC. The samples are dependent, and the distribution of the matched-pair differences between the measurements for the population is approximately uniform if the number of matched pairs is 30 or greater. O D. The samples are dependent, and the distribution of the matched-pair differences between the measurements for the population is approximately normal if the number of matched pairs is less than 30. 1: Weights Person Before After 1 226 202 2 214 195 207 193 4 186 172 202 196 6 197 181 7 242 231 8 191 193 is greater than O falls between does not fall between O reject O do not reject O sufficient O insufficient O is greater than O is less than or equal to O reject O do not reject O below O within or above (1) (2) (3) (4) (5) (6) O insufficient (7) (8) O is O is not O sufficient is less than or equal to
1. A new weight-loss program claims that participants will lose an average of more than 10 pounds after completing it. The accompanying data table shows the weights of eight individuals before and after the program. Complete parts (a) through (e) below. Click the icon to view the data table. a. Perform a hypothesis test using a = 0.05 to determine if the average weight loss was more than 10 pounds for participants in the weight-loss program. Let Ha be the population mean of matched-pair differences for the weight before the program minus the weight after the program. State the null and alternative hypotheses. Choose the correct answer below. O B. Ho: Ha s 10 O A. Ho Hg s 10 H: Pa < 10 H: Hg + 10 OD. Ho: Hg # 10 OC. Ho: Pa < 10 H: Hg 2 10 H: Hg = 10 O E. Ho: Ha s 10 OF. Ho: Ha = 10 H,: Hg # 10 H,: Hg > 10 b. Calculate the appropriate test statistic and interpret the results of the hypothesis test using a=0.05. The test statistic is (Round to two decimal places as needed.) The critical value(s) is(are) (Use a comma to separate answers as needed. Round to two decimal places as needed.) Interpret the results of the hypothesis test. Since the test statistic (1) the critical value(s), (2) the null hypothesis. There is (3) evidence that the mean score is lower after the weight-loss program. c. Identify the p-value and interpret the result. p-value = (Round to three decimal places as needed.) Interpret the result Since the p-value (4). the significance level, (5) the null hypothesis. There is (6) evidence that the mean score lower after the weight-loss program. d. Construct a 90% confidence interval to estimate the average weight loss for individuals in the program. Interpret the results. UCLj = LCLJ (Round to two decimal places as needed.)
Transcribed Image Text:1. A new weight-loss program claims that participants will lose an average of more than 10 pounds after completing it. The accompanying data table shows the weights of eight individuals before and after the program. Complete parts (a) through (e) below. Click the icon to view the data table. a. Perform a hypothesis test using a = 0.05 to determine if the average weight loss was more than 10 pounds for participants in the weight-loss program. Let Ha be the population mean of matched-pair differences for the weight before the program minus the weight after the program. State the null and alternative hypotheses. Choose the correct answer below. O B. Ho: Ha s 10 O A. Ho Hg s 10 H: Pa < 10 H: Hg + 10 OD. Ho: Hg # 10 OC. Ho: Pa < 10 H: Hg 2 10 H: Hg = 10 O E. Ho: Ha s 10 OF. Ho: Ha = 10 H,: Hg # 10 H,: Hg > 10 b. Calculate the appropriate test statistic and interpret the results of the hypothesis test using a=0.05. The test statistic is (Round to two decimal places as needed.) The critical value(s) is(are) (Use a comma to separate answers as needed. Round to two decimal places as needed.) Interpret the results of the hypothesis test. Since the test statistic (1) the critical value(s), (2) the null hypothesis. There is (3) evidence that the mean score is lower after the weight-loss program. c. Identify the p-value and interpret the result. p-value = (Round to three decimal places as needed.) Interpret the result Since the p-value (4). the significance level, (5) the null hypothesis. There is (6) evidence that the mean score lower after the weight-loss program. d. Construct a 90% confidence interval to estimate the average weight loss for individuals in the program. Interpret the results. UCLj = LCLJ (Round to two decimal places as needed.)
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