A new type of force was discovered by physicists witl the following expression: a Fnew = + Be* + 3x* where alpha & beta are constants, and x is th position. The expression above was obtained from the interaction of a massless Higgs Boson (a type c particle) and a black hole. Quantum physicists then decides to design and buil. a machine that is able to move the Higgs Boson from X2 to x1. How much work should the machine do t achieve this feat? (For simplicity, consider that ne energy is lost in the process) Solution To determine the work done we apply the following X; W = dx Evaluating the above, we get W = for the limits from xj to xf substituting x1 and x2 as the limits, the work done i expressed as W = x1 x12 - x22 )

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A new type of force was discovered by physicists witl
the following expression:
a
Fnew = + Be* + 3x*
where alpha & beta are constants, and x is th
position. The expression above was obtained from
the interaction of a massless Higgs Boson (a type c
particle) and a black hole.
Quantum physicists then decides to design and buil.
a machine that is able to move the Higgs Boson from
X2 to x1. How much work should the machine do t
achieve this feat? (For simplicity, consider that ne
energy is lost in the process)
Solution
To determine the work done we apply the following
X;
W =
dx
Evaluating the above, we get
W =
for the limits from xj to xf
substituting x1 and x2 as the limits, the work done i
expressed as
W =
x1
x12 - x22 )
Transcribed Image Text:A new type of force was discovered by physicists witl the following expression: a Fnew = + Be* + 3x* where alpha & beta are constants, and x is th position. The expression above was obtained from the interaction of a massless Higgs Boson (a type c particle) and a black hole. Quantum physicists then decides to design and buil. a machine that is able to move the Higgs Boson from X2 to x1. How much work should the machine do t achieve this feat? (For simplicity, consider that ne energy is lost in the process) Solution To determine the work done we apply the following X; W = dx Evaluating the above, we get W = for the limits from xj to xf substituting x1 and x2 as the limits, the work done i expressed as W = x1 x12 - x22 )
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