A new trainee pharmacist has an error rate of 0.19. Find the expected number of prescriptions until the first dispensing error, the median number of prescriptions until the first dispensing error, and the probability that the first dispensing error occurs among the first three prescriptions. a) what is the expected number?b) what is the probability that the first error is among the first thirteen descriptions? J2345678X91011121314151617TUA181920222222232426303112340.09P(X <= x) P(X = x)0.09000.17190.24640.31430.37600.43210.48320.52970.57210.61060.64560.67750.70650.73300.75700.77890.79880.8169567B8р9101112131415161718192021222324252627290.83340.84840.86200.87440.88570.89600.90540.91390.92160.92870.93510.09000.08190.07450.06780.06170.05620.05110.04650.04230.03850.03500.03190.02900.02640.02400.02190.01990.01810.01650.01500.01360.01240.01130.01030.00940.00850.00780.00710.0064 J2345678X91011121314151617A1811192022222223242628****3112340.09P(X <= x) P(X = x)0.09000.17190.24640.31430.37600.43210.48320.52970.57210.61060.64560.67750.70650.73300.75700.77890.79880.8169567B8р9101112131415161718192021222324252627290.83340.84840.86200.87440.88570.89600.90540.91390.92160.92870.93510.09000.08190.07450.06780.06170.05620.05110.04650.04230.03850.03500.03190.02900.02640.02400.02190.01990.01810.01650.01500.01360.01240.01130.01030.00940.00850.00780.00710.0064

Given that Error rate=0.19 According to the given information, it is a…

Answered: A new trainee pharmacist has an error…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A new trainee pharmacist has an error rate of 0.19. Find the expected number of prescriptions until the first dispensing error, the median number of prescriptions until the first dispensing error, and the probability that the first dispensing error occurs among the first three prescriptions. a) what is the expected number? b) what is the probability that the first error is among the first thirteen descriptions?

J
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8
X
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TU
A
18
19
20
222222
23
24
26
30
31
1
2
3
4
0.09
P(X <= x) P(X = x)
0.0900
0.1719
0.2464
0.3143
0.3760
0.4321
0.4832
0.5297
0.5721
0.6106
0.6456
0.6775
0.7065
0.7330
0.7570
0.7789
0.7988
0.8169
5
6
7
B
8
р
9
10
11
12
13
14
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18
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20
21
22
23
24
25
26
27
29
0.8334
0.8484
0.8620
0.8744
0.8857
0.8960
0.9054
0.9139
0.9216
0.9287
0.9351
0.0900
0.0819
0.0745
0.0678
0.0617
0.0562
0.0511
0.0465
0.0423
0.0385
0.0350
0.0319
0.0290
0.0264
0.0240
0.0219
0.0199
0.0181
0.0165
0.0150
0.0136
0.0124
0.0113
0.0103
0.0094
0.0085
0.0078
0.0071
0.0064

J
2
3
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5
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7
8
X
9
10
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13
14
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A
18
11
19
20
222222
23
24
26
28
****
31
1
2
3
4
0.09
P(X <= x) P(X = x)
0.0900
0.1719
0.2464
0.3143
0.3760
0.4321
0.4832
0.5297
0.5721
0.6106
0.6456
0.6775
0.7065
0.7330
0.7570
0.7789
0.7988
0.8169
5
6
7
B
8
р
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
29
0.8334
0.8484
0.8620
0.8744
0.8857
0.8960
0.9054
0.9139
0.9216
0.9287
0.9351
0.0900
0.0819
0.0745
0.0678
0.0617
0.0562
0.0511
0.0465
0.0423
0.0385
0.0350
0.0319
0.0290
0.0264
0.0240
0.0219
0.0199
0.0181
0.0165
0.0150
0.0136
0.0124
0.0113
0.0103
0.0094
0.0085
0.0078
0.0071
0.0064

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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