A new sneaker claims that it can make male athletes jump higher. A sample of 47 male athletes were asked to jump once with their own sneakers on and once wearing the new sneakers. The average jump increased by 2.15 inches with the new sneakers with a standard deviation of 1.38 inches. What is the standard error of the 95% confidence interval for the average jump increase?

Q: Use two confidence intervals to compare the two players, when it comes to points per game. For 33…

A: Followings are the Explanation of the question  Use the t test of confidence interval because the…

Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were Next question…

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Q: Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two…

A: x¯1=69, s1=19, n1=38x¯2=32, s2=14, n2=37

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A: Given information is :n=50x=$248.47S=$27.43And also given that 95% confidence interval is…

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A: given data, n=16x¯=31.32s=30.42CI=0.95α=1-0.95=0.05df=n-1=16-1=15we  have to construct the 95%…

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A: It is given that the sample mean is 32 and the population standard deviation is 4.1.

Q: Dana is a math professor who usually teaches in-person but has recently started teaching online.…

A: Given that, mean , μ=76.5standard deviation,σ=19.1and sample mean(class-average),x =68.4 and sample…

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: Given,sample size(n)=55sample mean(x)=32standard deviation(σ)=4.1α=1-0.90=0.1α2=0.05z0.05 =1.645

Q: The average weight of 36 randomly selected school buses was 4150 pounds with a standard deviation of…

A: Given data,x=4150σ=480n=36z-value at 99% confidence is Zc=2.576

Q: 15. A random sample of 100 visitors to a popular theme park spent an average of $142 on the trip…

A: SOLUTION: Given average x=142          standard deviation σ=47.5          random sample n=100

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A:

Q: If a school district takes a random sample of 75 Math SAT scores and finds that the average is 433,…

A:

Q: A study was conducted to determine the effectiveness of hypnotism on reducing pain. Using standard…

A: Sample 1(before hypnosis): n1=8x¯1=8.713s1=2.177 Sample 2(after hypnosis): n2=8x¯2=5.588s2=2.608

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A: Given information- Sample size, n = 45 Significance level, α = 0.10 Sample mean, x-bar = $90 Sample…

Q: An agronomist would like to estimate the average weight of all Indian River County grapefruits. The…

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A: The summary of statistics is, The degree of freedom is,

Q: e chips per cookie for Big Chip cookies? Round your answers to one decimal place.

A: Let X be the random variable such that number of chocolate chips per cookie for Big Chip cookies x̅:…

Q: 2. In a recent study of 35 college students, the mean number of hours per week that they played…

A: According to the given information in this question  We need to find the 95% confidence interval

Q: Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two…

A: Consider µD is the mean ALT levels for individuals who drink alcohol and the µND is the mean ALT…

Q: Twelve dieters lost an average of 7.1 pounds in 6 weeks when given a special diet plus a  herbal…

A: Given,To, construct a 95% confidence interval for the difference of the means.

Q: A musicologist is currently writing a report about pop songs in the late 2010s. As a part of her…

A: Givensample size(n)=222Mean(x)=3.05standard deviation(σ)=0.3

Q: If a school district takes a random sample of 80 Math SAT scores and finds that the average is 497,…

A:

Q: If a school district takes a random sample of 89 Math SAT scores and finds that the average is 497,…

A: From the provided information, Sample size (n) = 89 Sample mean (x̅) = 497 Population standard…

Q: In a survey, 24 people were asked how much they spent on their child's birthday party. The results…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: A survey of college students reported that in a sample of 371 male students, the average number of…

A: Obtain the 98% confidence interval for the difference between men and women in the mean number of…

Q: The marketing director concluded, with 95% confidence, that between $113.36 and $130.64 contains the…

A: Given: Sample size,n=40Sample mean x¯=122Sample standard deviation s=27confidence level,c =95% =…

Q: In a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with…

A:

Q: We have developed a series of questions to measure job satisfaction of bus drivers in London,…

A:

Q: recent survey of 7 social networking sites has a mean of 13.47 million visitors for a specific…

A: We need to construct the 99%99\%99% confidence interval for the population mean μ\muμ. The following…

Q: A group of students go to a lake that you fished in, and caught 28 adult striped bass fish. The mean…

A: Obtain the 95% confidence interval for the population mean of adult striped bass for that lake. The…

Q: find the 99% confidence interval of the mean number of miles driven per day by all truckers

A: It is given that  Average = 540 Population standard deviation = 40 Sample size = 90

Q: Suppose scores on exams in Biology are normally distributed with an unknown population mean and a…

A: given data σ = 5.4n = 60 x¯ = 81find 90% ci for μ = ?

Q: If a school district takes a random sample of 89 Math SAT scores and finds that the average is 494,…

A:

Q: shoppers at the mall spend the same amount of money on average the day after Thanksgiving compared…

A: Given that    Sample sizes n1=56      , n2=43       Sample means X̄1= 145     , X̄2=123    , ?1 =46…

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Q: For a random sample of  70  overweight men, the mean of the number of pounds that they were…

A: Here, n = 70, CL = 0.99, x=28, and σ=3.8

Q: It is known that rats run a standard maze in an average of 25.4 seconds. A researcher is trying to…

A: Sample size n =43 Sample mean=23.6 Standard deviation =5.1

Q: company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that…

A: We have given that  Sample size n = 80 Sample mean = 325.5 Standard deviation s=10.3 90%confidence…

Q: On average, adults spend approximately 5 hours per night in NREM (non-rapid eye movement) sleep. A…

A: The 99% confidence interval for the the true mean hours of NREM sleep per night who use a weighted…