A new production process is being contemplated for the manufacture of stainless steelbearings. Measurements of the diameters of random samples of bearings from the old andthe new processes produced the following data:Old:16.3 15.9 15.8 16.2 16.1 16.015.7 15.8 15.9 16.1 16.3 16.115.8 15.7 15.8 15.7New:15.9 16.2 16.0 15.8 16.1 16.115.8 16.0 16.2 15.9 15.7 16.215.8 15.8 16.2 16.3Can you conclude at the 5% level that one process yields a different mean size bearingthan the other?a.b.Can you conclude at the 5% level that the variance of the new procedure is lower thanthe older procedure?

Consider the measurements of the diameter form the old process as 1 and the measurements of the…

Answered: A new production process is being…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The following data are the measures of the diameters of 36 rivet heads in 1/100 of an inch:6.723 6.774 6.703 6.781 6.702 6.623 6.755 6.666 6.666 6.641 6.761 6.7326.802 6.722 6.761 6.761 6.685 6.665 6.626 6.726 6.762 6.703 6.785 6.7616.671 6.703 6.721 6.746 6.816 6.787 6.665 6.765 6.767 6.729 6.829 6.790a) Organize and Present the data in to Tabular form.b) Construct a Relative Frequency Histogram, Frequency Curve and Frequency Polygon of the data.c) Analyze whether or not there is any clear indication that the sample came from a population that hasNormal distribution.
The diameters of ball bearings produced in a manufacturing process can be described using a uniform distribution over the interval 8.5 to 10.5 millimeters. What is the mean diameter of ball bearings produced in this manufacturing process? A. 10 millimeters B. 10.5 millimeters C. 9.5 millimeters D. 9 millimeters
Find the sample standard deviation
A survey of the opinions of property owners about a street widening project was taken to determine whether the resulting opinion was related to the distance of front footage. A randomly selected sample of 100 property owners was contacted and the results are shown below. Opinion Front-Footage For Undecided Against Under 45 feet 12 4 4 45 – 120 feet 35 5 30 Over 120 feet 3 2 5 What is the computed value of chi-square? 5.4787 4.9985 9.2784 7.9842 11.0355
To determine if their 14 oz filling machine is properly adjusted, Harvey Soft Drinks has decided to use an X-Chart which uses the range to estimate the variability in the sample. J. Answer How to enter your answ Table Step 1 of 7: What is the Center Line of the control chart? Round your answer to three decimal places. Control Chart Period 1 2 3 4 5 6 7 8 9 10 11 Select the Copy Table button to copy all values. To select an entire row or column, either click on the row or column header or use the Shift and arrow keys. To find the average of the selected cells, select the Average Values button. Copy Table Average Values The average of the selected cell(s) is 14.000. Copy Value Sample Mean Sample Range 14.0060 0.04 0.04 0.04 0.10 0.08 0.09 0.07 0.05 0.05 0.06 0.07 obs1 obs2 obs3 obs4 obs5 14.00 13.99 14.03 14.01 14.00 14.02 14.05 14.05 14.01 14.04 14.0340 14.02 14.01 14.05 14.04 14.02 14.0280 14.04 13.97 14.05 13.95 14.00 14.0020 13.96 14.01 14.00 14.04 14.02 14.0060 13.96 14.00 14.00…
Listed below are the measured radiation absorption rates ( in 5 - number summary . W/kg) corresponding to 11 cell phones . Use the given data to construct a boxplot and identify the 1.49,1.25, 1.38, 1.04, 1.46, 1.31, 1.28, 0.73, 1.41, 0.58, 1.36
I need help for figuring out how to explain parts a and b.
A variable is normally distributed with mean 15 and standard deviation 3. Use your graphing calculator to find each of the following areas. Write your answers in decimal form. Round to the nearest thousandth as needed. a) Find the area to the left of 14. b) Find the area to the left of 12. c) Find the area to the right of 13. d) Find the area to the right of 16. e) Find the area between 12 and 25. Question Help: D Post to forum Calculator Submit Question
Analyze the following data. Assume the true value of L (the length of a table) is 93.40cm. L(cm) 93.2 93.3 93.9 92.8 93.5 93.4 92.9 a) What are the mean and standard deviation of this data sample? b) What is the uncertainty of the mean? c) Report the measured value of L. d) What is the relative discrepancy between the measured value of L and its true value? Suppose you have a second set of data for the same quantity that gives the following result: L = (93.90 ± 0.02) cm. e) Is this value more or less precise than the first value? f) Is this value more or less accurate than the first value? g) Do the two values agree given their uncertainties? h) What is the relative discrepancy between the two values?
Please use the accompanying Excel data set or accompanying Text file data set when completing the following exercise. A machine produces metal rods used in an automobile suspension system. A random sample of 15 rods is selected and the diameter is measured. The resulting data (in millimeters) are as follows: No. 2 3 4 6 7 9. 10 11 12 13 14 15 Dia. 8.28 8.19 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24 Use the data above to calculate a 95% two-sided confidence interval on the mean rod diameter. Assume the data are normally distributed. (a) Calculate the sample mean and standard deviation. Round the sample mean and the sample standard deviation to 2 and 3 decimal places respectively (e.g. 98.76 and 98.765). i S = (b) Calculate the 95% two-sided confidence interval on the true mean rod diameter. Round you answers to 3 decimal places (e.g. 98.765). i Statistical Tables and Charts
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 38 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 94 of the 111 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 #P2 Hy:P1 =P2 O B. Ho: P1 =P2 H1: P1 P2 H1: P1 #P2 Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? the null hypothesis. There sufficient evidence to support the claim that echinacea…
The lengths in millimetres (mm) of 60 runner beans taken from a particular crop were measured and found to be normally distributed. The runner beans were given ID numbers and their lengths to the nearest millimetre are recorded in the table below. a) Select a sample of 12 runner beans using systematic sampling and the random number 4 for the first selection. Write your sample in a table with headings, as demonstrated below. Runner bean ID Length (mm) Lengths of runner beans (mm) Runner bean Length(mm) Runner bean Length(mm) Runner bean Length(mm) ID Number ID Number ID Number 150 21 156 41 201 165 22 182 42 165 3 179 23 166 43 177 4 153 24 200 44 210 181 25 185 45 189 205 26 203 46 187 198 27 195 47 188 8. 171 28 170 48 179 9 210 29 180 49 142 10 168 30 210 50 175 11 186 31 194 51 175 12 179 32 188 52 177 13 188 33 160 53 190 14 175 34 189 54 162 146 35 170 55 187 15 172 36 189 56 168 16 164 37 167 57 167 17 160 38 178 58 187 18 152 39 197 59 166 19 40 210 60 204 20 209

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