A new process has been developed for applying photoresist to 125-mm silicon wafers used in manufacturing integrated circuits. Ten wafers were tested, and the following photoresist thickness measurements (in angstroms × 1000) were observed: 13.3987, 13.3957, 13.3902, 13.4015, 13.4001, 13.3918, 13.3965, 13.3925, 13.3946, and 13.4002. (For your convenience, we have calculated sample mean: 13.4 and sample standard deviation: 0.0039. You can use them directly.) (a) Test the hypothesis that mean thickness is 13.4 × 1000 Å. Use a = 0.2 and assume a two- sided alternative. (b) Find a 90% two-sided confidence interval on mean photoresist thickness. Assume that thickness is normally distributed.
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- Need help. Will give thumbs up! Data typed below and attached as an image. TSERofReturn AcmeRofReturn -1.99167 -1.03712 2.64815 3.04528 -0.58856 0.44802 -0.76395 0.60781 -0.81178 2.51735 -0.14212 1.70972 0.17677 -0.27609 0.54349 1.18672 -0.09428 0.49632 0.3681 -3.08347 0.60727 1.4182 1.3726 0.1878 -0.8915 -1.81699 1.8031 0.975 -0.26967 1.85853 2.42493 2.33005 -0.95528 -0.48742 -0.28562 -0.15591 -2.13517 -1.67924 -0.85961 1.57905 1.0856 -4.09194 -1.06689 -0.43368 0.04922 1.22281 3.2381 -0.55675 1.05371 -0.23124 -1.1785 -5.10525 1.11749 0.5909 -0.01456 1.70857 1.13344 0.93883 2.6641 0.92507 -1.33795 0.9294 -1.65683 -1.93668 -2.21489 -5.10648 -1.19445 0.47456 -0.461 0.19373 0.6551 -0.44915 1.5161 -1.11084 3.42943 2.58471 -0.3175 1.17337 -0.47695…Need help! Will give thumbs up! Thank you. Data is given below. TSERofReturn AcmeRofReturn -1.99167 -1.03712 2.64815 3.04528 -0.58856 0.44802 -0.76395 0.60781 -0.81178 2.51735 -0.14212 1.70972 0.17677 -0.27609 0.54349 1.18672 -0.09428 0.49632 0.3681 -3.08347 0.60727 1.4182 1.3726 0.1878 -0.8915 -1.81699 1.8031 0.975 -0.26967 1.85853 2.42493 2.33005 -0.95528 -0.48742 -0.28562 -0.15591 -2.13517 -1.67924 -0.85961 1.57905 1.0856 -4.09194 -1.06689 -0.43368 0.04922 1.22281 3.2381 -0.55675 1.05371 -0.23124 -1.1785 -5.10525 1.11749 0.5909 -0.01456 1.70857 1.13344 0.93883 2.6641 0.92507 -1.33795 0.9294 -1.65683 -1.93668 -2.21489 -5.10648 -1.19445 0.47456 -0.461 0.19373 0.6551 -0.44915 1.5161 -1.11084 3.42943 2.58471 -0.3175 1.17337 -0.47695 -1.08238…A study was carried out to determine the influence of a trace elementfound in soil on the yield of potato plants grown in that soil, defined asthe weight of potatoes produced at the end of the season. A large fieldwas divided up into 14 smaller sections for this experiment. For eachsection, the experimenter recorded the amount of the trace elementfound (in milligrams per metre squared) and the corresponding weightof the potatoes produced (in kilograms). This information is presentedin the worksheet ‘Dataset5’ in the Excel document. Define X as thetrace element amount and Y as the yield.1. Draw a scatterplot of your data set.Page 52. Calculate the coefficients of a linear equation to predict the yieldY as a function of X.3. Calculate the correlation coefficient for the paired data values.4. Set up the framework for an appropriate statistical test to establish if there is a correlation between the amount of the trace element and the yield. Explain how having the scatterplot referredto…
- The dotplot shows the body mass index (BMI) for 132 randomly surveyed people from a certain country. a. A BMI of more than 40 is considered morbidly obese. Report the number of morbidly obese shown in the dotplot. b. Report the percentage of people who are morbidly obese. Compare this with a recent estimate that 3% of people from the country were morbidly obese. a. From the people surveyed, how many people would be considered morbidly obese? The number of people considered morbidly obese is : 16 20 24 28 32 36 40 44 48 52 56 60 64 BMI QThe age of a tree can be determined by counting each annual growth ring in the trunk of the tree. A common measure of the size of a tree is the "diameter at breast height" DBH. "Breast height" is defined as 4 ½ feet above the uphill side of the tree. Consider the following data on 12 northern red oaks from southwestern Wisconsin: 11 15 28 1.5 1.0 6.0 45 12 52 16.5 11.0 | 10.5 9.0 Age(years) | 97 93 88 81 75 57 1.0 DBH(inch) | 12.5 12.5 8.0 9.5 d) What is the range of validity of this model?The group of items chosen from the population is called the а. ехample O b. [oll O c. sample O d. data
- Need help. Will give thumbs up! Data typed below. Thank you! TSERofReturn AcmeRofReturn -1.99167 -1.03712 2.64815 3.04528 -0.58856 0.44802 -0.76395 0.60781 -0.81178 2.51735 -0.14212 1.70972 0.17677 -0.27609 0.54349 1.18672 -0.09428 0.49632 0.3681 -3.08347 0.60727 1.4182 1.3726 0.1878 -0.8915 -1.81699 1.8031 0.975 -0.26967 1.85853 2.42493 2.33005 -0.95528 -0.48742 -0.28562 -0.15591 -2.13517 -1.67924 -0.85961 1.57905 1.0856 -4.09194 -1.06689 -0.43368 0.04922 1.22281 3.2381 -0.55675 1.05371 -0.23124 -1.1785 -5.10525 1.11749 0.5909 -0.01456 1.70857 1.13344 0.93883 2.6641 0.92507 -1.33795 0.9294 -1.65683 -1.93668 -2.21489 -5.10648 -1.19445 0.47456 -0.461 0.19373 0.6551 -0.44915 1.5161 -1.11084 3.42943 2.58471 -0.3175 1.17337 -0.47695 -1.08238…b). What is the minimum calculated value necessary to reach the .01 alpha level with 3 degrees of freedom in a Chi-Square cross-tabulation?in the table below, what data is inputted in spss for a chi-square analysis? Irregular Seat Belt Use? Yes No Texted While Driving 1737 2048 Did not Text While Driving 1945 2775
- Solve for the mean plant height of the plants in replication under the following observations: Plant 1 = 15 cm, Plant 2= 20 cm, Plant 3= 15 cm, Plant 4= 23 cm, Plant 5= 15 cm. Show solutionA simple telephone system consists of two end offices and a single toll office to which each end office is connected by a 1-MHz full-duplex trunk. The average telephone is used to make four calls per 8-hour workday. The mean call duration is 6 min. Ten percent of the calls are long-distance (i.e., pass through the toll office). What is the maximum number of telephones an end office can support? (Assume 4 kHz per circuit.)The driver of a certain bus line traveled 1000 km in four sections of 250 km each, with speeds of 92 km / h, 85 km / h, 95 km / h and 80 km / h, respectively. Calculate the average speed with which he made the trip and compare it with the harmonic mean of the data.