A new diet is developed to help people lose weight. 50 people tried the diet and had an average weight loss of 8 pounds over 30 days with a standard deviation of 2 pounds. A control group of 100 people tried a standard diet of fruits and vegetables also had an average weight loss of 9 pounds with a standard deviation of 1.2 pounds. Using a 5% significance determine if the new diet is better than eating fruits and vegetables. Take as population 1 the group on the new diet. Give the hypotheses. Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is more than the average weight loss on the fruit and vegetable diet. Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is less than the average weight loss on the fruit and vegetable diet. Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is not equal to the average weight loss on the fruit and vegetable diet. O No answer text provided.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 1GP
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Question 8: give the conclusion
A new diet is developed to help people lose weight. 50 people tried the
diet and had an average weight loss of 8 pounds over 30 days with a
standard deviation of 2 pounds. A control group of 100 people tried a
standard diet of fruits and vegetables also had an average weight loss of 9
pounds with a standard deviation of 1.2 pounds. Using a 5% significance
determine if the new diet is better than eating fruits and vegetables. Take
as population 1 the group on the new diet.
Give the hypotheses.
Null: There is no difference in the average weight loss between the two diets.
Alternative: The average weight loss on the new diet is more than the average
weight loss on the fruit and vegetable diet.
Null: There is no difference in the average weight loss between the two diets.
Alternative: The average weight loss on the new diet is less than the average
weight loss on the fruit and vegetable diet.
Null: There is no difference in the average weight loss between the two diets.
Alternative: The average weight loss on the new diet is not equal to the average
weight loss on the fruit and vegetable diet.
O No answer text provided.
Transcribed Image Text:A new diet is developed to help people lose weight. 50 people tried the diet and had an average weight loss of 8 pounds over 30 days with a standard deviation of 2 pounds. A control group of 100 people tried a standard diet of fruits and vegetables also had an average weight loss of 9 pounds with a standard deviation of 1.2 pounds. Using a 5% significance determine if the new diet is better than eating fruits and vegetables. Take as population 1 the group on the new diet. Give the hypotheses. Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is more than the average weight loss on the fruit and vegetable diet. Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is less than the average weight loss on the fruit and vegetable diet. Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is not equal to the average weight loss on the fruit and vegetable diet. O No answer text provided.
Give the conclusion.
Reject the null since the test statistic is in the rejection region.
Fail to reject the null since the test statistic is not in the rejection region.
Transcribed Image Text:Give the conclusion. Reject the null since the test statistic is in the rejection region. Fail to reject the null since the test statistic is not in the rejection region.
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