A new car worth $27,000 is depreciating in value by $3000 per year. Complete parts (a) through (c). a. Write a formula that models the car's value, y, in dollars, after x years. b. Use the formula from part (a) to determine after how many years the car's value will be $15,000. c. Graph the formula from part (a) in the first quadrant of a rectangular coordinate system. Then, show your solution to part (b) on the graph. C a. A formula that models the car's value, y, in dollars, after x years is (Type an equation.) b. After years, the car's value will be $15,000. (Type a whole number.) c. Choose the correct graph below. O A. OB. OC. O D. Ay Ay Q Q 10 10+ Ay 27,000+ 10 M 27,000- 27000 Q 27000 hots

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### Depreciation of a Car's Value

**Problem Statement:**
A new car worth $27,000 is depreciating in value by $3,000 per year. Complete parts (a) through (c):

a. Write a formula that models the car's value, \( y \), in dollars, after \( x \) years.

b. Use the formula from part (a) to determine after how many years the car's value will be $15,000.

c. Graph the formula from part (a) in the first quadrant of a rectangular coordinate system. Then, show your solution to part (b) on the graph.

---

**Solution:**

**a. Formula Development:**
A formula that models the car's value, \( y \), in dollars, after \( x \) years is:
\[ 
y = 27000 - 3000x 
\]

**b. Determining Time for Given Value:**
To find after how many years the car's value will be $15,000, we set up the equation:
\[
15000 = 27000 - 3000x
\]
Solving for \( x \):
\[
15000 = 27000 - 3000x \\
3000x = 27000 - 15000 \\
3000x = 12000 \\
x = \frac{12000}{3000} \\
x = 4
\]
So, after 4 years, the car's value will be $15,000.

**c. Choosing the Correct Graph:**
Below are the graphs representing the model:

- **Graph A** shows a linear decrease from $27,000 to $0 over 9 years.
- **Graph B** shows a linear decrease from $27,000 to $0 over 10 years.
- **Graph C** and **Graph D** seem not relevant for linear depreciation of car value as they do not have meaningful x-axis or y-axis labels corresponding to the car's value depreciation scenario.

The correct graph should be option **B**, which accurately represents the depreciation model \( y = 27000 - 3000x \).

**Graph B**: This graph has the y-axis representing the car's value in dollars and the x-axis representing time in years. It shows a starting value of $27,000 when \( x = 0 \) and a linear decline to $0 over a span of
Transcribed Image Text:### Depreciation of a Car's Value **Problem Statement:** A new car worth $27,000 is depreciating in value by $3,000 per year. Complete parts (a) through (c): a. Write a formula that models the car's value, \( y \), in dollars, after \( x \) years. b. Use the formula from part (a) to determine after how many years the car's value will be $15,000. c. Graph the formula from part (a) in the first quadrant of a rectangular coordinate system. Then, show your solution to part (b) on the graph. --- **Solution:** **a. Formula Development:** A formula that models the car's value, \( y \), in dollars, after \( x \) years is: \[ y = 27000 - 3000x \] **b. Determining Time for Given Value:** To find after how many years the car's value will be $15,000, we set up the equation: \[ 15000 = 27000 - 3000x \] Solving for \( x \): \[ 15000 = 27000 - 3000x \\ 3000x = 27000 - 15000 \\ 3000x = 12000 \\ x = \frac{12000}{3000} \\ x = 4 \] So, after 4 years, the car's value will be $15,000. **c. Choosing the Correct Graph:** Below are the graphs representing the model: - **Graph A** shows a linear decrease from $27,000 to $0 over 9 years. - **Graph B** shows a linear decrease from $27,000 to $0 over 10 years. - **Graph C** and **Graph D** seem not relevant for linear depreciation of car value as they do not have meaningful x-axis or y-axis labels corresponding to the car's value depreciation scenario. The correct graph should be option **B**, which accurately represents the depreciation model \( y = 27000 - 3000x \). **Graph B**: This graph has the y-axis representing the car's value in dollars and the x-axis representing time in years. It shows a starting value of $27,000 when \( x = 0 \) and a linear decline to $0 over a span of
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