A neutral molecule is polarized in the proximity of a 10muC charge. It can be modeled as two equal and opposite point charges, e and -e, separated by 0.5 angstroms (10^-10m or 0.1nm). What is the net force on the molecule by the 10muC charge if the distance between them is 1 meter?
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A neutral molecule is polarized in the proximity of a 10muC charge. It can be modeled as two equal and opposite point charges, e and -e, separated by 0.5 angstroms (10^-10m or 0.1nm). What is the net force on the molecule by the 10muC charge if the distance between them is 1 meter?
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- please help asap!A.) Which of the following statements are true? Choose all that are. The charge on particle A is 6 µC. The charge on particle B is 346 µC. The two particles are 58 cm apart. FE,A on B = FE,B on A- Electrostatically, electrons are repelled by neutrons. Quadrupling the distance between two charges increases the electric force between them by a factor of 16. For two charges with opposite polarities, FE > 0. In Coulomb's Law, k is the spring constant.Two charged small spheres are 20 cm apart and the magnitude of the force of repulsion between them is 4.57 10− ^21 N. If one sphere carries a charge q1 = −1.6 μC, a. What charge (q2) must be present on the other sphere? (5 pts.) b. Is charge q2 positive or negative? How do you know? (2 pts.) c. Find the number of electrons present on q1.
- The figure below shows three small, charged beads, all lying along the horizontal axis. Bead A, at left, has a 6.45 nC charge. Bead B has a 1.40 nC charge and is 3.00 cm to the right of A. Bead C has a-2.05 nC charge and is 2.00 cm to the right of B. 3.00 cm 9 9 -Select- 2.00 cm- Q (a) What is the magnitude (in N/C) of the electric field at a point 2.00 cm to the right of A? N/C (b) A fourth bead with a charge of -5.00 nC is placed at this point. What are the magnitude (in N) and direction of the net electric force on it? magnitude N directioned An isolated water molecule is modeled as two point charges ±0.700e separated by 0.0580 nm. Its rotational inertia is 2.93 × 10-47 kg-m² about the axis shown in the figure below. The molecule is in a uniform electric field of magnitude 783 N/C. What is the maximum possible torque on the molecule due to the electric field? Axis of rolation F 5.09E-27 ± 3% N-m Explanation The expression for the torque on a dipole in an electric field is 7 = qEd sin e.Answered: X https://porta x B 3.2 Explorir g x Learning ac x Learning ac x .content-service.brightspace.com ScormEngineinterface defauitui/player/modlem.html?configuration=88030417-4 3. Examine the charge distribution in the diagram below. 4.0x10:5 q3 24cm q1 q2 +) 24cm 2. 5 5. a. Determine the net force charge acting at g1 (+ 2.0 x 10 C), caused by q2 (- 4.0 x 10 C) and g3 (-4.0 x 10 C) Be sure to include a free body diagram 5. representing the force acting at q1 in your solution. b. Determine the net electric field acting at q1
- Q9. In Figure given below the four particles form a square of edge length a = 5.00 cm and have charges ql =+10.0 nC, q2=-20.0 nC, q3 = +20.0 nC, and q4=-10.0 nC. In unit-vector notation, what net electric field do the particles produce at the square's center? Answer: (1.02 x 10-11 N/C)j^In the figure, the particles have charges q1 = -q2 = 550 nC and q3 = -q4 = 97 nC, and distance a = 6.2 cm. What are the (a) x and (b) y components of the net electrostatic force on particle 3?Three neutral metal balls A, B and Care suspended by cotton threads with B touching C. A negatively charged rod is brought close to A and C is touched with a finger. The finger is then removed under the presence of the rod. After the rod is removed, the charge on the balls will be A A: neutral B: negative C: negative OA: positive B: negative C: negative OA: positive B: negative C: positive A: neutral B: neutral C: neutral BXC OA: neutral B: positive C: positive
- A3B Q3 d₁ d₂ d3 d4 Three point charges Q₁ = -2.64 nC, Q2 = 3.24 nC and Q3 = 3.45 nC are shown in the figure. The distance in the figure are: d₁ = 1.10 cm, d₂ = 1.47 cm, d3 = 1.54 cm and d4 = 1.32 cm. The figure is not to scale. Use k=8.99 × 10⁹ Nm²/C². (a) If a proton is released from rest at point *B, how fast is it moving when it is very far away from the three charges? VC = (b) How fast would the proton need to be moving very far away from the three charges to reach *B with a speed of 9.78 x 105 m/s? VD= (c) If an electron is released from rest very far away from the three charges shown, how fast would it be moving at *B? VE = (d) How fast must an electron be moving at *B to come to rest very far away from the three charges? UF =2. Suppose we have an infinitely long wire with uniform line charge density λ = -1.00 × 10-⁹ C/m lying flat on the ground. The wire is fully stretch out (not coiled up). a) How strong is the repulsive electric force on an electron placed 1.00 m above the wire? Hint: this is another Gauss' Law problem, just with some extra calculations after. b) How does this compare the gravitational force on the electron pulling it down?