A negatively charged particle, having a mass m = 5.89 x10 rest in a uniform electric field of magnitude 4000 N/C; the uniform electric field points in the negative x direction, as shown in the figure. Assume that the force of gravity is negligible compared to the electric force acting on the charged particle. -23 grams and a charge q = - 1.60x10- C, is released from In the following, consider the period of time which starts at the instant when the particle is released (from rest) and ends at the instant when the particle has traveled a distance of 20.0 cm (along a straight line) in the uniform electric field. +y UNIFORM E (4000 N/C) 8. The direction of the electric force which the field exerts on the particle is directed in A. the positive y direction. B. the negative y direction. C. the positive x direction. D. the negative x direction. 9. The magnitude of the electric force which the field exerts on the particle is equal to A. 6.40x 10-16 N. B. 4.00x 10 N. C. 6.40x10 N. D. 6.40x 10 19N. E. - 4000 N. 10. The work done on the particle by the electric force during the time it takes the particle to travel 20.0 cm in the electric field is A. - 1.28 x 10-16 J. B. 1.28 x 10-16 J. C. 1.28 x 1018 J. D. 6.40 x 10-16 J. E. 1.28 x 10 14 J. 11. At the instant when the particle has traveled 20.0 cm in the uniform field, the kinetic energy of the particle is A. 1.28 x 10 18 J. B. 6.40 x 10-16 J. C. 1.28 x 10-14 J. D. - 1.28 x 10-16 J. E. 1.28 x 10-16 J. 12. True or False: acceleration of the charged particle has a magnitude of 1.09 x 107 A. True. B. False. 13. At the instant when the particle has traveled 20.0 cm in the uniform field, the speed of the charged particle is A. 2.08 x 10' m. B. 1.47 x 10 m/. C. 4.66x 10* m. D. 6.59 x 10 m/. E. 6.59 x 10° m 14. Find the time which passes from the instant of the particle's release (from rest) until the particle has traveled 20.0 cm in the uniform field. A. 96.2 microseconds. B. 3.03 microseconds. C. 0.136 milliseconds. D. 4.29 microseconds. E. 6.07 microseconds.
A negatively charged particle, having a mass m = 5.89 x10 rest in a uniform electric field of magnitude 4000 N/C; the uniform electric field points in the negative x direction, as shown in the figure. Assume that the force of gravity is negligible compared to the electric force acting on the charged particle. -23 grams and a charge q = - 1.60x10- C, is released from In the following, consider the period of time which starts at the instant when the particle is released (from rest) and ends at the instant when the particle has traveled a distance of 20.0 cm (along a straight line) in the uniform electric field. +y UNIFORM E (4000 N/C) 8. The direction of the electric force which the field exerts on the particle is directed in A. the positive y direction. B. the negative y direction. C. the positive x direction. D. the negative x direction. 9. The magnitude of the electric force which the field exerts on the particle is equal to A. 6.40x 10-16 N. B. 4.00x 10 N. C. 6.40x10 N. D. 6.40x 10 19N. E. - 4000 N. 10. The work done on the particle by the electric force during the time it takes the particle to travel 20.0 cm in the electric field is A. - 1.28 x 10-16 J. B. 1.28 x 10-16 J. C. 1.28 x 1018 J. D. 6.40 x 10-16 J. E. 1.28 x 10 14 J. 11. At the instant when the particle has traveled 20.0 cm in the uniform field, the kinetic energy of the particle is A. 1.28 x 10 18 J. B. 6.40 x 10-16 J. C. 1.28 x 10-14 J. D. - 1.28 x 10-16 J. E. 1.28 x 10-16 J. 12. True or False: acceleration of the charged particle has a magnitude of 1.09 x 107 A. True. B. False. 13. At the instant when the particle has traveled 20.0 cm in the uniform field, the speed of the charged particle is A. 2.08 x 10' m. B. 1.47 x 10 m/. C. 4.66x 10* m. D. 6.59 x 10 m/. E. 6.59 x 10° m 14. Find the time which passes from the instant of the particle's release (from rest) until the particle has traveled 20.0 cm in the uniform field. A. 96.2 microseconds. B. 3.03 microseconds. C. 0.136 milliseconds. D. 4.29 microseconds. E. 6.07 microseconds.
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