A national health organization says that 30% of teenagers have tried smoking cigarettes. A health agency in a small city decides to see if this proportion holds true for its own city. The city has a total of 3500 teenagers. The health agency randomly selects 280 teenagers, and finds that 56 of them have smoked cigarettes. What is the sample proportion? Group of answer choices .016 .536 .08 .2 You want to make a 99% confidence interval for the proportion of teenagers in the city who have smoked. What critical value Z* would you use? Group of answer choices 1.28 1.645 1.96 2.58 When making a confidence interval, what is the Standard Error that you use? (round to 4 places after the decimal)

Q: Use the sample data and confidence level given below to complete parts  (a)    A research institute…

A: It is given that x is 587 and n is 912.

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A: Given x=450 n=600

Q: Use the given confidence interval to find the margin of error and the sample mean. .734, .760

A: From the given information, the confidence interval is (0.734, 0.760). It can be expressed in,

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A: It is given that the sample size (n) is 260 and the number of positive trials (x) is 150.

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A:

Q: ​(Round to three decimal places as​ needed.) Part 2 ​b) Identify the value of the margin of error E.…

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A:

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A:

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A:

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A: Given data, n1=50x1=35p1=x1n1 =3550=0.7x2=40n2=60p2=40 60=0.67z-value at 95% confidence is Zc=1.96

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A: Sample size n=z2(p*q)/e2

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A: given data  n = 350 x = 76 we have to interprete 99% confidence intervl.

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A: GivenBuilding 90% , 95% and 99% confidence interval for the same statistics

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A:

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A:

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A: Level of significance ɑ=0.25

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A:

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A:

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Q: Lower %3D

A:

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A: The formula for the sample size is as follows:

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A: Correct answer is d. All of the above.

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A: Given that  Margin of error =E=6.50%=0.0650 99% confidence.