A Narrow Band Frequency Modulated signal, with =10 kHz, ₁=100 MHz, 4f₁ = 5kHz is applied to a frequency multiplier with a factor of 3 to convert it to a Wide band FM signal, the output of the multiplier has a WBFM with, =10 kHz, f₁₂-300 MHz, 4 =15kHz Ⓒfm² = 30 kHz, fa=300 MHz, 4f = 5kHz ⒸS² = 30 kHz, f₁2-300 MHz, 4₂=15kHz S² = 10 kHz, fa=100 MHz, 4/₂ = 5kHz

Q: Choose The Correct Answer 1. What is the main advantage of using FSK over ASK for digital communication? A. FSK is more resistant to noise and interference. B. FSK is more power efficient. C. FSK requires less complex circuitry. D. FSK can transmit data over a wider range of frequencies. 2. What is the main disadvantage of using FSK over ASK for digital communication? A. FSK is more prone to noise and interference. B. FSK is less power efficient. C. FSK requires more complex circuitry. D. FSK can only transmit data over a narrow range of frequencies. 3.How does the data rate of a digital communication system using FSK compared to the data rate of system using ASK with the same bandwidth and signal-to-noise ratio (SNR)? A. The FSK system has a higher data rate. B. The ASK system has a higher data rate. C. The data rate is the same for both systems. D. It is not possible to compare the data rate without more information. 4.How does the spectral efficiency of…

From figure b) What is the oscillation frequency?  c) What is the oscillation amplitude?  d) What is the phase difference between Vout1 and Vout2? vout 1 = orange wave  vout 2 = purple wave

Prove that the Vout = (- Rf / Rin ) vin