A motorcycle has a constant acceleration of 3.95 m/s². Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a)19.4 to 29.4 m/s, and (b)49.4 to 59.4 m/s? (a) Number i Units (b) Number i Units
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- A speeding car is traveling at a constant speed of 39.5 m/s when it passes a police car. The police car accelerates at 9 m/s2. How far will the police car have to travel to reach the same speed as the speeding car? ROUND THE ANSWER TO 1 DECIMAL PLACE. INPUT NUMERICAL VALUE ONLY.In the given equation, v = At² + Bx, 'v' is the velocity, 'x'is displacement, and 't'is the time. Then the dimensions of A and B are ; B= LT-1 b) A = LT¯1 ; B= T¯1 B = LT-2 ; B = T¯1 a) A = T ; c) A = T-1 d) A = LT-3 O b O aFor a short time, the speed v of a car, in m / s, is given by v = at2 + bt3, where t is the time in seconds. The units of a and b are, respectively, a) m/s^2; m/s^3 b) m/s^4; m/s^5 c) s^3/m; s^4/m d) m.s^2; m.s^4 e) m/s^3; m/s^4
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