A motor delivers 500 hp to the shaft, which is tubular and has an outer diameter of 2 in. The shaft is rotating at 92 rad/s. 1 hp = 550 ft lb/s. (Figure 1) !!

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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2.
A motor delivers 500 hp to the shaft, which is tubular and
has an outer diameter of 2 in. The shaft is rotating at
92 rad/s. 1 hp = 550 ft - lb/s. (Figure 1)
Figure
1 of 1
6 in.
Transcribed Image Text:2. A motor delivers 500 hp to the shaft, which is tubular and has an outer diameter of 2 in. The shaft is rotating at 92 rad/s. 1 hp = 550 ft - lb/s. (Figure 1) Figure 1 of 1 6 in.
Determine its largest inner diameter of the shaft if the allowable shear stress for the material is Tallow = 25 ksi.
Express your answer to three significant figures and include the appropriate units.
HA
d; =
Value
Units
Submit
Previous Answers Reguest Answer
Transcribed Image Text:Determine its largest inner diameter of the shaft if the allowable shear stress for the material is Tallow = 25 ksi. Express your answer to three significant figures and include the appropriate units. HA d; = Value Units Submit Previous Answers Reguest Answer
Expert Solution
Step 1

Given that,

Power delivered motor, P=500 hp,Outer diamter of shaft, do=2 in,Speed of shaft, ω=92 rad/sec,Allowable shear stress of shaft material, τall=25 ksi,

Convert the unit of the power from hp to lb. ft/sec.

P=500 hpP=500 550 lb.ft/sec1 hpP=275000 lb.ft/sec,

Calculate the maximum torque by using the following equation:

T=PωT=27500092T=2989.1304 lb.ft

 

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