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A motion has a equation Z R(+) = (+ cos (5+)) ²² + (4+)² + (+6in (5+)) K Find the acceleration vetor cut time t-uas: A. A (u) = (-55m (20) - 100 (os (20) ; 0; 10 cos (20) - 100 cos (20)) B. A (u) = (-5 sin (20) - 100 cos (20); 0; 5 cos (20)-(00 cos (20)) C. A (u) = (-1050₂²60) - 100 cos (20) ; 0; 56015 (20) - 100son (20)) D. A (4)-(-10 si (20) - 100 cos (20) ; 0; 10 cos (20) -100 cos (20))

A motion has a equation Z R(+) = (+ cos (5+)) ²² + (4+)² + (+6in (5+)) K Find the acceleration vetor cut time t-uas: A. A (u) = (-55m (20) - 100 (os (20) ; 0; 10 cos (20) - 100 cos (20)) B. A (u) = (-5 sin (20) - 100 cos (20); 0; 5 cos (20)-(00 cos (20)) C. A (u) = (-1050₂²60) - 100 cos (20) ; 0; 56015 (20) - 100son (20)) D. A (4)-(-10 si (20) - 100 cos (20) ; 0; 10 cos (20) -100 cos (20))

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Ngày: Tuần: 2 3 4 5 6 7 CN A motion has a equation R(+) = (+ cos (5+)) ??² + (4+);} + (+sin(5)) K² Find the acceleration vector at time + - 4 as: A. A (u) = (-55m (20) - 100 (os (20) ; 0; 10 cos (20) - 100 cus (20)) B. A (u) = (-5 sin (20) - 100 cos (20) ; 0 ; 5 cos (20) - (00 COS (20)). C. A (u) = (-105m₂ (20) - 100 cos (20) ; 0; 5 605 (20) - 1008 BM (20)) D. A (4) - (-10 30₂00) - 100 cos (20) ; 0; 10 cos (20) - 100 cos (70))
Transcribed Image Text:Ngày: Tuần: 2 3 4 5 6 7 CN A motion has a equation R(+) = (+ cos (5+)) ??² + (4+);} + (+sin(5)) K² Find the acceleration vector at time + - 4 as: A. A (u) = (-55m (20) - 100 (os (20) ; 0; 10 cos (20) - 100 cus (20)) B. A (u) = (-5 sin (20) - 100 cos (20) ; 0 ; 5 cos (20) - (00 COS (20)). C. A (u) = (-105m₂ (20) - 100 cos (20) ; 0; 5 605 (20) - 1008 BM (20)) D. A (4) - (-10 30₂00) - 100 cos (20) ; 0; 10 cos (20) - 100 cos (70))
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