A monatomic ideal gas initially has a temperature of 330k and preassure of 3x105 Pa. The gas expands from a volume of 500cm3 to a volume of 1500cm3. l) Calculate the change in internal energy (in Joules), if the expansion is adiabatic. the answer must be => (150)ln(3)J
A monatomic ideal gas initially has a temperature of 330k and preassure of 3x105 Pa. The gas expands from a volume of 500cm3 to a volume of 1500cm3. l) Calculate the change in internal energy (in Joules), if the expansion is adiabatic. the answer must be => (150)ln(3)J
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Question
A monatomic ideal gas initially has a temperature of 330k and preassure of 3x105 Pa. The gas expands from a volume of 500cm3 to a volume of 1500cm3.
l) Calculate the change in internal energy (in Joules), if the expansion is adiabatic.
the answer must be => (150)ln(3)J
NOTICE : The work in adiabatic process equals the change in internal energy. So, w = - Δu = - (g/2*n*r*Δt)
pΔV=nRΔT, thus: Δu = g/2*pΔV
The answer is right, so, calculate the change in internal energy using this formula : Δu = g/2*pΔV
Transcribed Image Text:-1
T₁.V₁¹T₂.V₂¹
2
-1
Expert Solution
Step 1
We know that in adiabatic process dQ = 0
Hence in this problem the change in internal energy is equal to the workdone.
So we can solve this problem as following in step 2.
Step by step
Solved in 2 steps with 1 images
