A monatomic ideal gas expands in a reversible diabatic process. The initial temperature of the gas mounts to T¡ and the mole number is equal to n. The inal temperature Tf = Ti/4. Calculate the change in Is volume. O a. Vf/Vj=1/8 O b. Vf/V;=1/8 O c. Vf/V;=4 O d. Vf/Vj=2 O e. Vf/Vj=8
A monatomic ideal gas expands in a reversible diabatic process. The initial temperature of the gas mounts to T¡ and the mole number is equal to n. The inal temperature Tf = Ti/4. Calculate the change in Is volume. O a. Vf/Vj=1/8 O b. Vf/V;=1/8 O c. Vf/V;=4 O d. Vf/Vj=2 O e. Vf/Vj=8
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![A monatomic ideal gas expands in a reversible
adiabatic process. The initial temperature of the gas
amounts to T¡ and the mole number is equal to n. The
final temperature Tf = Ti/4. Calculate the change in
its volume.
O a. Vf/V¡=1/8
O b. Vf/Vj=1/8
O c. Vf/Vj=4
O d. Vf/Vj=2
O e. Vi/V;=8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6799d1f8-d9b0-4143-9614-a8bbfa7ac22c%2F53939abf-da23-4458-b53a-bf5fbec6e0a2%2Fr8l3b28_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A monatomic ideal gas expands in a reversible
adiabatic process. The initial temperature of the gas
amounts to T¡ and the mole number is equal to n. The
final temperature Tf = Ti/4. Calculate the change in
its volume.
O a. Vf/V¡=1/8
O b. Vf/Vj=1/8
O c. Vf/Vj=4
O d. Vf/Vj=2
O e. Vi/V;=8
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