A model airplane of mass m flies with a speed |v| in a horizontal circle at the end of a control wire of length L. Circular path of airplane Wire a) Draw a free-body diagram for the force acting on the plane. Assume that the aerodynamic lift force acts in a direction perpendicular to the wings of the airplane, and that the wire is at an angle below the horizontal. b) Calculate the lift and tension forces if m= 0.750kg, |v| = 35.0m/s, L = 60.0m and 20.0°.

A model airplane of mass m flies with a speed |v| in a horizontal circle at the end of a control wire of length L. Circular path of airplane Wire a) Draw a free-body diagram for the force acting on the plane. Assume that the aerodynamic lift force acts in a direction perpendicular to the wings of the airplane, and that the wire is at an angle below the horizontal. b) Calculate the lift and tension forces if m= 0.750kg, |v| = 35.0m/s, L = 60.0m and 20.0°.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The following equation may be used to estimate the take-off ground run for an aircraft: Equation has been attached as an image. Calculate the take-off ground run, from a runway at ISA-SL conditions, for a twin engine aircraft for which the following data may be assumed Aircraft lift-off speed 155 knots Max take-off gross weight 220 tonnes Wing planform area (S) 358 m Wing CL (t/o flaps deployed, a = 0) 1.1 Wing span 53.18 m Oswald efficiency factor, e 0.7 KGE = CD(IGE) / Co(OGE) 0.4 Co sum (fuselage, wing, tailplane and nacelle) 0.015 Co for undercarriage 0.021 Co for flaps at taking-off setting 0.0073 Coefficient of rolling friction, u 0.02 Engine thrust (assumed constant) 310 kN per engine It may be assumed that 1knot = 0.51444 m/s It may be assumed that 1knot = 0.51444 m/s
A particle P of mass m = 6 kg is travel- ing at vp = -8i m/s and has a net force F = -5i N acting on it. At a certain instant, 0 = 25° and the distance from O and Hp, at this instant. P.2) %3D to P is L = 3 m. Calculate HP. %3D j L.
4. A skydiver is falling at terminal velocity toward earth moving at 80m/s. The weight of the skydiver is 800N. What rate of heat generation is created in the air behind them (Joules per second)? If they continue at constant speed, how far vertically would they need to fall to loose gravitational energy equal to one gallon of gasoline? (Energy in one gallon of gas is 150MJ).
(Review experimental scaling) A lightweight parachute is being designed for military use. Its diameter D is 20 ft and the total weight W of the falling payload, parachute, and equipment is 190 lb. The design terminal settling speed V. (or terminal velocity) of the parachute at this weight is 16 ft/s. A one-twelfth scale model of the parachute is tested in a wind tunnel. The wind tunnel temperature and pressure are the same as those of the prototype, which is 70 °F and standard atmospheric pressure. a) Calculate the drag coefficient of the prototype. (Hint: At terminal velocity, speed is constant so weight is in equilibrium with aerodynamic drag.) b) At what speed should the wind tunnel be run in order to achieve dynamic similarity? c) Find the aerodynamic drag force of the model parachute in the wind tunnel in pounds. Payload
2. A student team is to design a human-powered submarine for a design competition. The overall length of the prototype submarine is 4.85 m, and its student designers hope that it can travel fully submerged through water at 0.440 m/s. The water is freshwater (a lake) at T = 15 °C. The design team builds a one-fifth scale model to test in their university's wind tunnel, as shown in the Fig. A shield surrounds the drag balance strut so that the aerodynamic drag of the strut itself does not influence the measured drag. The air in the wind tunnel is at 25 °C and at one standard atmosphere pressure. At what air speed do they need to run the wind tunnel in order to achieve similarity? Take for water at T = 15 °C and atmospheric pressure, p = 999.1 kg/m³ and µ = 1.138 × 10-³ Pa.s. Take for air at T = 25 °C and atmospheric pressure, p = 1.184 kg/m³ and µ = 1.849 × 10-³ Pa.s. V Por P Wind tunnel test section Model Shield FD Drag balance Strut
L. y X VA A VB PLANE OF CONTACT BY UBC Engineering On an air hockey table, two pucks of identical mass collide in the middle of the rink. Puck A had an initial m velocity vA 1.9? and puck B had an initial velocity vB = 3.2j The plane of contact can be thought of as a line angled 0 = 34° above the x-axis. If the coefficient of 0.5 between the pucks, what are the velocities of the pucks after the impact? || m according to the x-y axis shown. restitution is e =
Expanded.4 deals with the conservation of momentum principle. Using the conservation of momentum principle to solve this problem is mandatory. Solution using other approaches will be automatically considered false. For the problem related to Expanded.4, sketches of the system showing: • the respective initial and final velocity and position coordinates and the frame of reference considered • the forces acting on the system of considered, in other words, a free body diagram (FBD) are mandatory. Their absences will automatically make the problem false. A B F 300 mm 600 mm Knowing the angular velocity of rotation of the bob, 4-kg, is 3 rad/s when the length of the rope is 600mm and the angle is 44°, what is the angular velocity of the rope if the length of the rope becomes 300mm while the angle reduces of 6°?
A 250 g ball collides with a wall. The figures below show the ball’s velocity and force exerted on the ball by the wall. What is vfx, the final velocity of the ball? Paste the completed Bar Chart below. 1. identify the system 2. draw a quick sketch of the initial state of the object(s) 3. do a momentum bar chart
This exercise is part of a series of problems aimed at modeling a situation by progressively refining our model to take into account more and more parameters. This progressive approach is very close to what professional scientists do! context We want to lower a suspended load in a controlled way so that it hits the ground with a speed whose modulus is not too great. To slow down the descent, a spring has been added behind the mass (A), The suspended load (B) is connected by a rope passing through a pulley to this mass (A), which slides on a horizontal surface with friction. Information The masses of the charges A and B are known.The mass of the rope itself is negligible (very small compared to the loads).The pulley has negligible mass and can rotate without friction.The charge B is initially stationary and is at a known height h.The surface on which mass A sits is tilted upwards at a known angle theta from the horizontal.There is friction under mass A: the kinetic friction…
2. Refer to the figure below. In addition to the load at point D, if another load Q (Q=10F) along x direction acts at the center of the right end section of bar OABC, solve for the maximum load F with a safety factor of 2.0 using the maximum shear stress theory. Find the stresses at the origin point O. Assume the yield strength of the steel is 42 kpsi with v=0.3. Hints: The centroid of a semicircle lies at a distance of 4r/(3) measured along the vertical radius (r) or y-direction. 2 in. 1-in D. -in R. 1-in D. 12 in 15 in 1-in D.
Hello. Answer is s=0.42m (how far the spring goes down before stopping the object falling). I am uploading this question as the example answer's working out was bad I find it hard to follow. I would like to see working out how the calculations equate to the answer being s=0.42m
In a nutshell, a smaller rock is propelled into the air as a huge counterweight in the back falls down, effectively converting gravitational potential energy into kinetic energy for the rock and the weight. But, since the rock is smaller.. it is propelled at a much faster velocity! Let's say we wanted to hurl a 50 kg boulder at a castle wall 100 meters away. Our wooden structure for the trebuchet is 10 meters tall, so that is the maximum distance the counterweight can fall. Assuming the launch angle is a perfect 45 degrees, and the boulder is released from ground level, derive the needed mass of the counterweight that will give the boulder enough kinetic energy to reach the base of the castle walls. You may assume no energy is "lost" due to friction, and ALL the counterweight's gravitational potential energy is converted into the boulder's kinetic enerqy. (HINT: You will need to employ 2D kinematics to find the needed final velocity, then use that final velocity in an energy equation…