A metal with molar mass = 102.91 g/mol crystallizes in a face-centered cubic lattice with an edge length of 380.1 pm. What is its density? A. 0.777 g/cm³ хов.3.11 g/cm3 C. 1.55 g/cm3 D. 6.22 g/cm3 E. 12.4 g/cm3
A metal with molar mass = 102.91 g/mol crystallizes in a face-centered cubic lattice with an edge length of 380.1 pm. What is its density? A. 0.777 g/cm³ хов.3.11 g/cm3 C. 1.55 g/cm3 D. 6.22 g/cm3 E. 12.4 g/cm3
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A metal with molar mass =
102.91 g/mol crystallizes in a face-centered cubic lattice with an edge length of 380.1 pm. What is its density?
A. 0.777 g/cm3
B. 3.11 g/cm3
O C. 1.55 g/cm3
D. 6.22 g/cm3
E. 12.4 g/cm3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01e55177-61b2-4b42-9c0d-56b237a86a25%2F7da310c6-8eaa-4dbf-a891-9601088a646d%2F4a3pbe_processed.png&w=3840&q=75)
Transcribed Image Text:A metal with molar mass =
102.91 g/mol crystallizes in a face-centered cubic lattice with an edge length of 380.1 pm. What is its density?
A. 0.777 g/cm3
B. 3.11 g/cm3
O C. 1.55 g/cm3
D. 6.22 g/cm3
E. 12.4 g/cm3
Expert Solution
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Step 1) Given that
Given that :-
Molar mass = M = 102.91 g/mol
Edge length = a = 380.1 pm
{ but 1 pm = 10-12 m } & { 1m = 100 cm}
Edge length = a = 380.1 × 10-¹² (100cm)
Edge length = a = 380.1 × 10-10cm
Edge length = a = 3.801 × 10-8cm
Metal form FCC lattice
Number of Particles = Z = 4
Avogadro Number = N = 6.022 × 10²³
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