A metal anode has a standard reduction potential of minus 1.56 V and the cathode has a reduction potential of minus 1.16 V. What is the E° cel?
A metal anode has a standard reduction potential of minus 1.56 V and the cathode has a reduction potential of minus 1.16 V. What is the E° cel?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2.
![### Calculating Standard Cell Potential
**Problem:**
A metal anode has a standard reduction potential of minus 1.56 V and the cathode has a reduction potential of minus 1.16 V. What is the \( E^\circ_{\text{cell}} \)?
**Options:**
- ⃝ -2.72 V
- ⃝ +0.40 V
- ⃝ +2.72 V
- ⃝ -0.40 V
### Explanation:
To find the standard cell potential (\( E^\circ_{\text{cell}} \)), use the formula:
\[ E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} \]
Substitute the given values:
\[
E^\circ_{\text{cell}} = (-1.16 \, \text{V}) - (-1.56 \, \text{V})
\]
\[
E^\circ_{\text{cell}} = -1.16 \, \text{V} + 1.56 \, \text{V}
\]
\[
E^\circ_{\text{cell}} = +0.40 \, \text{V}
\]
Therefore, the correct answer is +0.40 V.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc02bfde4-a78d-4551-93f6-03d589a5c8dc%2Fb5b0e791-74d3-44b1-88d7-4b0c3234222a%2Fo1vzzel_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculating Standard Cell Potential
**Problem:**
A metal anode has a standard reduction potential of minus 1.56 V and the cathode has a reduction potential of minus 1.16 V. What is the \( E^\circ_{\text{cell}} \)?
**Options:**
- ⃝ -2.72 V
- ⃝ +0.40 V
- ⃝ +2.72 V
- ⃝ -0.40 V
### Explanation:
To find the standard cell potential (\( E^\circ_{\text{cell}} \)), use the formula:
\[ E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} \]
Substitute the given values:
\[
E^\circ_{\text{cell}} = (-1.16 \, \text{V}) - (-1.56 \, \text{V})
\]
\[
E^\circ_{\text{cell}} = -1.16 \, \text{V} + 1.56 \, \text{V}
\]
\[
E^\circ_{\text{cell}} = +0.40 \, \text{V}
\]
Therefore, the correct answer is +0.40 V.
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