A message has been encoded by assigning the numbers 1 to 26 to the letters a to z of the alphabet, respectively, and assigning 27 to a blank space. A message of this type can be decoded by finding the inverse of the encoding matrix and multiplying it times the coded message Use A¹ and the conversion table below to decode the following message The encoding matrix is A = The decoded message is abcdefghijklmnopq stuvwxyz blank 123456789 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 12-1 2 1-3 and the encoded message is 29.-1, 75.-19. -66, 50, 46, 41, 47,3 -38,65 -14 2 0 *****
A message has been encoded by assigning the numbers 1 to 26 to the letters a to z of the alphabet, respectively, and assigning 27 to a blank space. A message of this type can be decoded by finding the inverse of the encoding matrix and multiplying it times the coded message Use A¹ and the conversion table below to decode the following message The encoding matrix is A = The decoded message is abcdefghijklmnopq stuvwxyz blank 123456789 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 12-1 2 1-3 and the encoded message is 29.-1, 75.-19. -66, 50, 46, 41, 47,3 -38,65 -14 2 0 *****
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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