A medical research team wanted to perform a statistical inference procedure to see if there is a difference in the proportion of people that report headache pain relief within 30 minutes of taking either acetaminophen or ibuprofen. Volunteers that suffer from regular headaches were split into two groups: one who took acetaminophen at the onset of a headache and one group that took ibuprofen. Which of the following would be an appropriate null hypothesis for an inference test see if there is a difference between the two medications? (where A stands for acetaminophen users and I stands for ibuprofen users) A Ho: PA - Pr = 0 Ho: PA-Pr=0 C Ho: PA-Pr # 0 Ho: PA- Pr >0 |相

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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A medical research team wanted to perform a statistical inference procedure to see if there is a
difference in the proportion of people that report headache pain relief within 30 minutes of taking
either acetaminophen or ibuprofen. Volunteers that suffer from regular headaches were split into two
groups: one who took acetaminophen at the onset of a headache and one group that took ibuprofen.
Which of the following would be an appropriate null hypothesis for an inference test see if there is a
difference between the two medications? (where A stands for acetaminophen users and I stands for
ibuprofen users)
A
Ho: PA - Pr = 0
В
Ho: PA-Pr = 0
C
Ho: PA-Pr # 0
Ho: PA-Pr>0
Transcribed Image Text:A medical research team wanted to perform a statistical inference procedure to see if there is a difference in the proportion of people that report headache pain relief within 30 minutes of taking either acetaminophen or ibuprofen. Volunteers that suffer from regular headaches were split into two groups: one who took acetaminophen at the onset of a headache and one group that took ibuprofen. Which of the following would be an appropriate null hypothesis for an inference test see if there is a difference between the two medications? (where A stands for acetaminophen users and I stands for ibuprofen users) A Ho: PA - Pr = 0 В Ho: PA-Pr = 0 C Ho: PA-Pr # 0 Ho: PA-Pr>0
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