A medical investigation claims that the average number of infections per week at a hospital is 13.7. A random sample of 10 weeks had a mean number of 14.8 infections. The sample standard deviation is 1.3. Is there enough evidence to reject the investigator's claim at a = 0.05 ? [5m]
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- A data set of lumber estimates(dollars) has a mean of 5 and a standard deviation of 4.739, calculate the z-score of 15.321542. Z-Score = [three decimal places]On the planet of Mercury, 4-year-olds average 2.9 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.4 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(_______ ,______) I know that question a is (2.9,1.4) b. Find the probability that the child spends less than 1.3 hours per day unsupervised. c. What percent of the children spend over 3.4 hours per day unsupervised. % (Round to 2 decimal places) d. 82% of all children spend at least how many hours per day unsupervised? hours. Please help me understand how to do the rest.From a sample with n = 32, the mean duration of a geyser's eruptions is 3.42 minutes and the standard deviation is 1.12 minutes. Using Chebychev's Theorem, determine at least how many of the eruptions lasted between 1.18 and 5.66 minutes. At least of the eruptions lasted between 1.18 and 5.66 minutes. (Simplify your answer.)
- On the planet of Mercury, 4-year-olds average 3.1 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.6 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places where possible.b. Find the probability that the child spends less than 1.7 hours per day unsupervised. c. What percent of the children spend over 3.7 hours per day unsupervised. % (Round to 2 decimal places)d. 74% of all children spend at least how many hours per day unsupervised? hours.The president of a college wants to determine the mean number of units that college students take per semester. How large of a sample is required in order to be 99% sure that a sample mean will be off by no more than 1.25 units? An initial study suggested that the standard deviation is approximately 2.1 units.Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches. A particular man is 80 inches tall. Find the z-score of his height. (Round to two decimal places.)
- On the planet of Mercury, 4-year-olds average 3.2 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.7 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places if not otherwise specified.c. What percent of the children spend over 4.6 hours per day unsupervised. % (Round to 2 decimal places) d. 84.85% of all children spend at least how many hours per day unsupervised? hours. (Round to 2 decimal places)On the planet of Mercury, 4-year-olds average 3.2 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.3 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(,)b. Find the probability that the child spends less than 1.9 hours per day unsupervised. c. What percent of the children spend over 5.2 hours per day unsupervised. % (Round to 2 decimal places)d. 88% of all children spend at least how many hours per day unsupervised? hours.On the planet of Mercury, 4-year-olds average 3.1 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.6 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(,) b. Find the probability that the child spends less than 1.7 hours per day unsupervised. c. What percent of the children spend over 2.3 hours per day unsupervised. % (Round to 2 decimal places) d. 67% of all children spend at least how many hours per day unsupervised?
- On the planet of Mercury, 4-year-olds average 2.8 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.5 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places where possible. a. Find the probability that the child spends less than 3.1 hours per day unsupervised. b. 61% of all children spend at least how many hours per day unsupervised?On a recent quiz, the class mean was 74 with a standard deviation of 4.6. Calculate the z-score (to 2 decimal places) for a person who received score of 80. z-score: Is this unusual? O Not Unusual O Unusual