A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 26,000 miles and a standard deviation of 2400 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires? Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table, Tires that wear out by miles will be replaced free of charge. (Round to the nearest mile as needed.)

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 26,000 miles and a standard deviation of 2400
miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of
the tires?
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
Tires that wear out by
miles will be replaced free of charge.
(Round to the nearest mile as needed.)
Transcribed Image Text:A mechanic sells a brand of automobile tire that has a life expectancy that is normally distributed, with a mean life of 26,000 miles and a standard deviation of 2400 miles. He wants to give a guarantee for free replacement of tires that don't wear well. How should he word his guarantee if he is willing to replace approximately 10% of the tires? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Tires that wear out by miles will be replaced free of charge. (Round to the nearest mile as needed.)
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