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A mass weighing 32 pounds stretches a spring 2 feet. If the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 2 ft/s. Determine the equation of the motion and its solution x(t). O x" + 16x = 0 x (t) = - cos(41) – sin(47) O x" – 16x = 0 x (1) = cos(41) + sin(41)

A mass weighing 32 pounds stretches a spring 2 feet. If the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 2 ft/s. Determine the equation of the motion and its solution x(t). O x" + 16x = 0 x (t) = - cos(41) – sin(47) O x" – 16x = 0 x (1) = cos(41) + sin(41)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A mass weighing 32 pounds stretches a spring 2 feet. If the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 2 ft/s. Determine the equation of the motion and its solution x(t). O x" + 16x = 0 %3D x (1) = - cos(41) – sin(41) O x" – 16x = 0 %3D x (1) = cos(41) + sin(47) %3D O x" + 16x = 0 %3D x (t) = 2 cos(4t) – sin(4t) - O 16x" + x = 0 x (1) =D -글cos(41) - sin(41)
Transcribed Image Text:A mass weighing 32 pounds stretches a spring 2 feet. If the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 2 ft/s. Determine the equation of the motion and its solution x(t). O x" + 16x = 0 %3D x (1) = - cos(41) – sin(41) O x" – 16x = 0 %3D x (1) = cos(41) + sin(47) %3D O x" + 16x = 0 %3D x (t) = 2 cos(4t) – sin(4t) - O 16x" + x = 0 x (1) =D -글cos(41) - sin(41)
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