A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 9 inches below the equilibrium position. (a) Find the position x of the mass at the times t = 1/12, 1/8, n/6, 1/4, and 9n/32 s. (Use g = 32 ft/s² for the acceleration due to gravity.) x(n/12) = ft Χ(π/8) - ft x(π/6) - ft Χ (π/4 ) - ft x(9n/32) = ft (b) What is the velocity of the mass when t = 3n/16 s? ft/s In which direction is the mass heading at this instant? O downward O upward (c) At what times does the mass pass through the equilibrium position? , n = 0, 1, 2, ...
A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 9 inches below the equilibrium position. (a) Find the position x of the mass at the times t = 1/12, 1/8, n/6, 1/4, and 9n/32 s. (Use g = 32 ft/s² for the acceleration due to gravity.) x(n/12) = ft Χ(π/8) - ft x(π/6) - ft Χ (π/4 ) - ft x(9n/32) = ft (b) What is the velocity of the mass when t = 3n/16 s? ft/s In which direction is the mass heading at this instant? O downward O upward (c) At what times does the mass pass through the equilibrium position? , n = 0, 1, 2, ...
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 74E
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![A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 9 inches below the equilibrium position.
(a) Find the position x of the mass at the times t = t/12, t/8, 1/6, 1/4, and 9n/32 s. (Use g = 32 ft/s² for the acceleration due to gravity.)
Χ (π/12)
ft
%3D
Χ (π/8) -
ft
x(T/6) =
ft
Χ (π/4) -
ft
x(9п/32) %3
ft
(b) What is the velocity of the mass when t = 31/16 s?
ft/s
In which direction is the mass heading at this instant?
O downward
O upward
(c) At what times does the mass pass through the equilibrium position?
, п %3D 0, 1, 2, ...](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faeb81122-6fbf-4c63-aaf5-71689ff4fea7%2Ff6049cd3-c57c-4b98-9a5f-62ae05ae6e1a%2Fn2tm7y_processed.png&w=3840&q=75)
Transcribed Image Text:A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 9 inches below the equilibrium position.
(a) Find the position x of the mass at the times t = t/12, t/8, 1/6, 1/4, and 9n/32 s. (Use g = 32 ft/s² for the acceleration due to gravity.)
Χ (π/12)
ft
%3D
Χ (π/8) -
ft
x(T/6) =
ft
Χ (π/4) -
ft
x(9п/32) %3
ft
(b) What is the velocity of the mass when t = 31/16 s?
ft/s
In which direction is the mass heading at this instant?
O downward
O upward
(c) At what times does the mass pass through the equilibrium position?
, п %3D 0, 1, 2, ...
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