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A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 3 inches below the equilibrium position. (a) Find the position x of the mass at the times t = 1/12, n/8, 1/6, n/4, and 97/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.) x(п/12) %3D x(п/8) %3D x (π/6) x (π/4) - x(9п/32) %3D

A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 3 inches below the equilibrium position. (a) Find the position x of the mass at the times t = 1/12, n/8, 1/6, n/4, and 97/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.) x(п/12) %3D x(п/8) %3D x (π/6) x (π/4) - x(9п/32) %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Specifically a DiffEq problem. Question in pic below.

Answer: x(pi/12) = -1/8 ft,  x(pi/8) = -1/4 ft,  x(pi/6) = -1/8 ft,  x(pi/4) = 1/4 ft,  x(9pi/32) = 1/4sqrt(2) ft

A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 3 inches below the equilibrium position. (a) Find the position x of the mass at the times t = 1/12, n/8, 1/6, n/4, and 97/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.) x(п/12) %3D x(п/8) %3D x (π/6) x (π/4) - x(9п/32) %3D
Transcribed Image Text:A mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 3 inches below the equilibrium position. (a) Find the position x of the mass at the times t = 1/12, n/8, 1/6, n/4, and 97/32 s. (Use g = 32 ft/s? for the acceleration due to gravity.) x(п/12) %3D x(п/8) %3D x (π/6) x (π/4) - x(9п/32) %3D
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