A mass-spring system oscillates on a frictionless horizontal surface in simple harmonic motion with an amplitude A = 0.16 m. At what position (x = ?) would the kinetic energy of the system be equal to three times its elastic potential energy (K = 3U)? At x = +0.08 m

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A mass-spring system oscillates on a
frictionless horizontal surface in simple
harmonic motion with an amplitude A =
0.16 m. At what position (x = ?) would
the kinetic energy of the system be
equal to three times its elastic potential
energy (K = 3U)?
At x = +0.08 m
At x = +0.04 m
At x = +0.1 m
At x = +0.05 m
At x = +0.025 m
Consider a place where the gravity is
one-fourth the gravity on Earth (g' =
g/4), then the frequency of oscillation
of a simple pendulum in that place, f',
as compared to its frequency on earth
is:
Transcribed Image Text:4:48 A docs.google.com 0.2 sec 0.3 sec A mass-spring system oscillates on a frictionless horizontal surface in simple harmonic motion with an amplitude A = 0.16 m. At what position (x = ?) would the kinetic energy of the system be equal to three times its elastic potential energy (K = 3U)? At x = +0.08 m At x = +0.04 m At x = +0.1 m At x = +0.05 m At x = +0.025 m Consider a place where the gravity is one-fourth the gravity on Earth (g' = g/4), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is:
4:48
A docs.google.com
At x = ±0.1 m
At x = ±0.05 m
At x = +0.025 m
Consider a place where the gravity is
one-fourth the gravity on Earth (g' =
g/4), then the frequency of oscillation
of a simple pendulum in that place, f',
as compared to its frequency on earth
is:
f' = f/2
O f' = 2f
f' = 9f
f' = f/3
O f' = 4f
A simple pendulum is set into motion at
two different times with different initial
conditions. The first time: the bob is in
its equilibrium position and is given an
initial velocity +2 m/s. The maximum
height reached by the bob is h1,max
and the poried of motion ic T The
Transcribed Image Text:4:48 A docs.google.com At x = ±0.1 m At x = ±0.05 m At x = +0.025 m Consider a place where the gravity is one-fourth the gravity on Earth (g' = g/4), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: f' = f/2 O f' = 2f f' = 9f f' = f/3 O f' = 4f A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the poried of motion ic T The
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