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A mass-spring-damper system is shown below and the transfer function is given. Give below-find the spring constant, mass, and damping constant k.m.c of the system according to the looped Bode diagram. Reminder. The starting point of the red line corresponds to -26dB. C = 0.32. The red line the frequency corresponding to the inclined peak point is v3.2

A mass-spring-damper system is shown below and the transfer function is given. Give below-find the spring constant, mass, and damping constant k.m.c of the system according to the looped Bode diagram. Reminder. The starting point of the red line corresponds to -26dB. C = 0.32. The red line the frequency corresponding to the inclined peak point is v3.2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question 3: A mass-spring-damper system is shown below and the transfer function is given. Give below- find the spring constant, mass, and damping constant k.m.c of the system according to the looped Bode diagram. Reminder. The starting point of the red line corresponds to-26dB. C = 0.32. The red line the frequency corresponding to the inclined peak point is v3.2 Y(S) = G(s)R(s) 1 mss cs k Yay, k -- Katie The Presenter, c r(t) Jy(t) Genlik (dB) 0.01 -10 -20 -26 -30 -40 -50 0.01 Frequency (rad/sec) 0.1 0.1 1 3.2 10 100 1 10 100 Flour = 3.2 (= 0.32 0° -90⁰ 180° Faz (derece)
Transcribed Image Text:Question 3: A mass-spring-damper system is shown below and the transfer function is given. Give below- find the spring constant, mass, and damping constant k.m.c of the system according to the looped Bode diagram. Reminder. The starting point of the red line corresponds to-26dB. C = 0.32. The red line the frequency corresponding to the inclined peak point is v3.2 Y(S) = G(s)R(s) 1 mss cs k Yay, k -- Katie The Presenter, c r(t) Jy(t) Genlik (dB) 0.01 -10 -20 -26 -30 -40 -50 0.01 Frequency (rad/sec) 0.1 0.1 1 3.2 10 100 1 10 100 Flour = 3.2 (= 0.32 0° -90⁰ 180° Faz (derece)
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