### Problem StatementA mass of 1.25 kg stretches a spring 0.05 m. The mass is in a medium that exerts a viscous resistance of 4 N when the mass has a velocity of 4 m/s. The viscous resistance is proportional to the speed of the object. Suppose the object is displaced an additional 0.08 m and released.Find a function to express the object's displacement from the spring's natural position, in meters after \( t \) seconds. Let positive displacements indicate a stretched spring, and use \( 9.8 \: \frac{m}{s^2} \) as the acceleration due to gravity.\[ u(t) = \](Note: There are no graphs or diagrams in the provided image to describe.)

Solution, At the equilibrium position, F=mg-Fd-kx0=mg-Fd-kxkx=mg-FdSubstitute the given…

Answered: A mass of 1.25 kg stretches a spring…

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