A mass of 0.2 kg stretches a spring by 20 cm. The damping constant is c = 0.4. External vibrations create a force of F(t) = 0.2 cos 8t N. Find the steady-state solution. O "P up == Up = Up = 15 481 15 481 15 481 15 481 cos 8t + cos 8t - cos 8t - cos 8t + 16 481 16 481 16 481 16 481 sin 8t sin 8t sin 8t sin 8t
A mass of 0.2 kg stretches a spring by 20 cm. The damping constant is c = 0.4. External vibrations create a force of F(t) = 0.2 cos 8t N. Find the steady-state solution. O "P up == Up = Up = 15 481 15 481 15 481 15 481 cos 8t + cos 8t - cos 8t - cos 8t + 16 481 16 481 16 481 16 481 sin 8t sin 8t sin 8t sin 8t
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Transcribed Image Text:A mass of 0.2 kg stretches a spring by 20 cm. The damping constant is c = 0.4. External vibrations
create a force of F(t) = 0.2 cos 8t N. Find the steady-state solution.
O
O
up
==
Up
up
=
"P
15
481
15
481
15
481
15
481
cos 8t +
cos 8t -
cos 8t -
cos 8t +
16
481
16
481
16
481
16
481
sin 8t
sin 8t
sin 8t
sin 8t
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