A mass MI slides on a 45° inclined plane of height H as shown in Fig. 2-14. It is connected by a flexible cord of negligible mass over a small pulley (neglect its mass) to an equal-mass M2 hanging vertically as shown. The length of the cord is such that the masses can be held at rest both at height H / 2. The dimensions of the masses and the pulley are negligible compared to H. At time t = 0 the two masses are released. The acceleration of M2 downward is 1.43 m/s^2 and Box 2 will strike the ground at t = 0.84 /H. A) If M1 suddenly comes lose how much time would it take for M2 to reach the ground if H/2 = 4 m. Mass box 1 = 20 kg, Mass box 2 = 21 kg.|

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A mass MI slides on a 45° inclined plane of height H as shown in Fig. 2-14. It is
connected by a flexible cord of negligible mass over a small pulley (neglect its mass) to
an equal-mass M2 hanging vertically as shown. The length of the cord is such that the
masses can be held at rest both at height H / 2. The dimensions of the masses and the
pulley are negligible compared to H . At time t = 0 the two masses are released. The
acceleration of M2 downward is 1.43 m/s^2 and Box 2 will strike the ground at
t = 0.84 H.
A) If M1 suddenly comes lose how much time would it take for M2 to reach the
ground if H/2 = 4 m. Mass box 1 = 20 kg, Mass box 2 = 21 kg.|
AJ
M₂
H/2
M₂
45°
Transcribed Image Text:A mass MI slides on a 45° inclined plane of height H as shown in Fig. 2-14. It is connected by a flexible cord of negligible mass over a small pulley (neglect its mass) to an equal-mass M2 hanging vertically as shown. The length of the cord is such that the masses can be held at rest both at height H / 2. The dimensions of the masses and the pulley are negligible compared to H . At time t = 0 the two masses are released. The acceleration of M2 downward is 1.43 m/s^2 and Box 2 will strike the ground at t = 0.84 H. A) If M1 suddenly comes lose how much time would it take for M2 to reach the ground if H/2 = 4 m. Mass box 1 = 20 kg, Mass box 2 = 21 kg.| AJ M₂ H/2 M₂ 45°
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