A market researcher would 90 minutes per day with a standard deviation of 15 minutes per day. average college student spends watching sports. Suppose he does a preliminary study based LAUSE SALT 90 O 95 (a) Which of the following numbers gives the value of the point estimate? O 15 O 25 (b) Using the information given above, calculate the margin of error (in minutes) of the point estimate. Assume we would like to estimate the population mean with 95% confidence. (Use a table or technology. Round your answer to two decimal places.) 6.18 M = (t critical value) min (c) Suppose that the researcher is not content with the current margin of error. He would like the margin of error of the point estimate to be no more than 4 minutes with 95% confidence. The researcher is unwilling to trust that the sample standard deviation from his previous study accurately estimates the true population standard deviation. He does, however, know that college students tend to watch sports between 0 and 120 minutes per day. What is the minimum sample size needed to obtain this amount of precision? (Use a table or technology) 216.09 x n=(2 critical value). If If n is not a whole number, we will round up to the nearest whole number, college students

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A market researcher would like to know how much time the average college student spends watching sports. Suppose he does a preliminary study based upon a sample of 25 college students. The mean amount of time spent watching sports, by those in the sample, is
90 minutes per day with a standard deviation of 15 minutes per day.
LUSE SALT
(a) Which of the following numbers gives the value of the point estimate?
O 15
O 25
90
O 95
(b) Using the information given above, calculate the margin of error (in minutes) of the point estimate. Assume we would like to estimate the population mean with 95% confidence. (Use a table or technology. Round your answer to two decimal places.)
x
6.18
M = (t critical value) min
S
Vn
(c) Suppose that the researcher is not content with the current margin of error. He would like the margin of error of the point estimate to be no more than 4 minutes with 95% confidence. The researcher is unwilling to trust that the sample standard deviation from his
previous study accurately estimates the true population standard deviation. He does, however, know that college students tend to watch sports between 0 and 120 minutes per day. What is the minimum sample size needed to obtain this amount of precision? (Use
a table or technology.)
216.09
x
n = (z critical value)
(+)²³.
. If n is not a whole number, we will round up to the nearest whole number, college students
Transcribed Image Text:A market researcher would like to know how much time the average college student spends watching sports. Suppose he does a preliminary study based upon a sample of 25 college students. The mean amount of time spent watching sports, by those in the sample, is 90 minutes per day with a standard deviation of 15 minutes per day. LUSE SALT (a) Which of the following numbers gives the value of the point estimate? O 15 O 25 90 O 95 (b) Using the information given above, calculate the margin of error (in minutes) of the point estimate. Assume we would like to estimate the population mean with 95% confidence. (Use a table or technology. Round your answer to two decimal places.) x 6.18 M = (t critical value) min S Vn (c) Suppose that the researcher is not content with the current margin of error. He would like the margin of error of the point estimate to be no more than 4 minutes with 95% confidence. The researcher is unwilling to trust that the sample standard deviation from his previous study accurately estimates the true population standard deviation. He does, however, know that college students tend to watch sports between 0 and 120 minutes per day. What is the minimum sample size needed to obtain this amount of precision? (Use a table or technology.) 216.09 x n = (z critical value) (+)²³. . If n is not a whole number, we will round up to the nearest whole number, college students
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