A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employee receives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received is recorded and the number of defects on the most recent countertop produced is determined. The results are as follows. Hours of Training Defects per Countertop 15417033252451521862 The estimated regression line and the standard error are given. Defects per Countertop = 6.717822-1.004950(Hours of Training) se = 1.229787 Suppose a new employee has had 11 hours of training. What would be the 99% prediction interval for the number of defects per countertop? Round your answer to two decimal places.

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A manufacturing company that produces laminate for countertops is interested in studying the relationship
between the number of hours of training that an employee receives and the number of defects per
countertop produced. Ten employees are randomly selected. The number of hours of training each
employee has received is recorded and the number of defects on the most recent countertop produced is
determined. The results are as follows. Hours of Training Defects per Countertop
15417033252451521862 The estimated regression line and the standard error are given. Defects
per Countertop = 6.717822-1.004950(Hours of Training) se = 1.229787 Suppose a new employee has had
11 hours of training. What would be the 99% prediction interval for the number of defects per countertop?
Round your answer to two decimal places.
Transcribed Image Text:A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employee receives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received is recorded and the number of defects on the most recent countertop produced is determined. The results are as follows. Hours of Training Defects per Countertop 15417033252451521862 The estimated regression line and the standard error are given. Defects per Countertop = 6.717822-1.004950(Hours of Training) se = 1.229787 Suppose a new employee has had 11 hours of training. What would be the 99% prediction interval for the number of defects per countertop? Round your answer to two decimal places.
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