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A manufacturing company has developed a cost model, C(x) = 0.15x3 + 0.01x² + 2r + 120, where x is the number of items sold, in thousands. The sales price can be modeled by S(x) = 30 – 0.01x. Therefore, revenue is modeled by R(x) = x • S(x). The company's profit, P(x) = R(x) – C(x), could be modeled by %3D

A manufacturing company has developed a cost model, C(x) = 0.15x3 + 0.01x² + 2r + 120, where x is the number of items sold, in thousands. The sales price can be modeled by S(x) = 30 – 0.01x. Therefore, revenue is modeled by R(x) = x • S(x). The company's profit, P(x) = R(x) – C(x), could be modeled by %3D

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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please help me show my work to figure out this problem i want to make sure i am correct thank you so so much
A manufacturing company has developed a cost model, C(x) = 0.15x3 + 0.01x² + 2x + 120, where x is the number of items sold, in thousands. The sales price can be modeled by S(x) = 30 – 0.01x. Therefore, revenue is modeled by R(x) = x • S(x). The company's profit, P(x) = R(x) – C(x), could be modeled by (1) 0.15x3 + 0.02r² – 28x + 120 (2) -0.15x3 – 0.02r2 + 28x – 120 (3) -0.15x3 + 0.01x2 – 2.01x – 120 (4) –0.15x3 + 32x + 120
Transcribed Image Text:A manufacturing company has developed a cost model, C(x) = 0.15x3 + 0.01x² + 2x + 120, where x is the number of items sold, in thousands. The sales price can be modeled by S(x) = 30 – 0.01x. Therefore, revenue is modeled by R(x) = x • S(x). The company's profit, P(x) = R(x) – C(x), could be modeled by (1) 0.15x3 + 0.02r² – 28x + 120 (2) -0.15x3 – 0.02r2 + 28x – 120 (3) -0.15x3 + 0.01x2 – 2.01x – 120 (4) –0.15x3 + 32x + 120
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