A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weight is known to be normal, with a standard deviation of 0.4 ounces. A random sample of 25 boxes yielded a sample mean weight of 19.59 ounces. Test at the 1% significance level the null hypothesis that the population mean weight is at least 20 ounces. What are the null and alternative hypotheses for this test? OA. H₂: ≤20 H₁: μ> 20 OC. H₂ H₂ = 20 = 19.59 O A. Reject H, if OB. Reject H, if For this test at the significance level a with sample mean x, hypothesized mean Ho, population standard deviation o, sample size n, and za or Za/2, what is the form of the decision rule? c is correct x-Ho 0/√n OC. Reject Ho if x-Ho o/√n <-Za/2 or reject H, if ->Za x-Ho o/√√n Determine the appropriate value(s) of -Za. Za or ±Za/2- <-Za x-Ho 0/√n State the conclusion of this test. (Type an integer or a decimal.) x-Ho 0/√n the null hypothesis. There reject not reject ->Za/2 I (Round to two decimal places as needed. Use a comma to separate answers as needed.) Calculate the decision statistic. -2.33 OB. H₂:μ=20 H₁: μ#20 OD. H₂:μ ≥20 H,:μ < 20 is is not d is right answer significant evidence that the population mean weight is not at least 20 ounces.

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A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weight is known to be normal, with a standard deviation of
0.4 ounces. A random sample of 25 boxes yielded a sample mean weight of 19.59 ounces. Test at the 1% significance level the null hypothesis that the population mean weight is at
least 20 ounces.
What are the null and alternative hypotheses for this test?
OA. H₂: ≤20
H₁: μ> 20
OC. H₂: H=20
H₂ = 19.59
O A. Reject H, if
OB. Reject H if
OC. Reject Ho if
For this test at the significance level a with sample mean x, hypothesized mean Ho, population standard deviation o, sample size n, and za or Za/2, what is the form of the
decision rule?
c is correct
x-Ho
o/√√n
x-Ho
o/√n
x-Ho
o/√√n
<-Za/2 or reject H, if
->Za
<-Za
Determine the appropriate value(s) of -Za. Za or ±Za/2-
x-Ho
0/√n
State the conclusion of this test.
(Type an integer or a decimal.)
x-Ho
0/√n
the null hypothesis. There
-2.33
(Round to two decimal places as needed. Use a comma to separate answers as needed.)
Calculate the decision statistic.
reject
not reject
->Za/2
CIE
OB. H₂:μ=20
H₁: μ#20
OD. H₂ μ ≥20
H₁: μ<20
is
is not
d is right answer
significant evidence that the population mean weight is not at least 20 ounces.
Transcribed Image Text:A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weight is known to be normal, with a standard deviation of 0.4 ounces. A random sample of 25 boxes yielded a sample mean weight of 19.59 ounces. Test at the 1% significance level the null hypothesis that the population mean weight is at least 20 ounces. What are the null and alternative hypotheses for this test? OA. H₂: ≤20 H₁: μ> 20 OC. H₂: H=20 H₂ = 19.59 O A. Reject H, if OB. Reject H if OC. Reject Ho if For this test at the significance level a with sample mean x, hypothesized mean Ho, population standard deviation o, sample size n, and za or Za/2, what is the form of the decision rule? c is correct x-Ho o/√√n x-Ho o/√n x-Ho o/√√n <-Za/2 or reject H, if ->Za <-Za Determine the appropriate value(s) of -Za. Za or ±Za/2- x-Ho 0/√n State the conclusion of this test. (Type an integer or a decimal.) x-Ho 0/√n the null hypothesis. There -2.33 (Round to two decimal places as needed. Use a comma to separate answers as needed.) Calculate the decision statistic. reject not reject ->Za/2 CIE OB. H₂:μ=20 H₁: μ#20 OD. H₂ μ ≥20 H₁: μ<20 is is not d is right answer significant evidence that the population mean weight is not at least 20 ounces.
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