- A man whose weight is 0.80 kN is standing upright. By approximately how much is his femur shortened compared to when he is tying down? Assume that the compressive force on each femur is about half his weight. The average cross-section area of the femur is 8.0 cm² and the length of femur when lying down is 43.0cm
- A man whose weight is 0.80 kN is standing upright. By approximately how much is his femur shortened compared to when he is tying down? Assume that the compressive force on each femur is about half his weight. The average cross-section area of the femur is 8.0 cm² and the length of femur when lying down is 43.0cm
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![A man whose weight is 0.80 KN is standing upright. By
Papproximately how much is his femur shortened compared
to when he is tying down? Assume that the compressive
force on each femur is about half his weight. The average
cross-section area of the femur is 8.0 cm² and the length of
femur when lying down is 43.0cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F99c64d57-0b61-4806-9ae4-b27728805fc5%2F9d8fa04c-80f4-4a21-9292-9155023837eb%2F0p34bw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A man whose weight is 0.80 KN is standing upright. By
Papproximately how much is his femur shortened compared
to when he is tying down? Assume that the compressive
force on each femur is about half his weight. The average
cross-section area of the femur is 8.0 cm² and the length of
femur when lying down is 43.0cm
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