A man throws a coin off the edge of a cliff. The coin's initial velocity is 25.0 m/s directed at 40.0° with the face of the cliff, as shown in the figure. The coin hits the ground 3.75 s after being thrown and feels no appreciable air resistance as it falls. 25.0 m/s Cliff

A man throws a coin off the edge of a cliff. The coin's initial velocity is 25.0 m/s directed at 40.0° with the face of the cliff, as shown in the figure. The coin hits the ground 3.75 s after being thrown and feels no appreciable air resistance as it falls. 25.0 m/s Cliff

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Question

What is the velocity of the coin just before it hits the ground

A man throws a coin off the edge of a cliff. The coin's initial velocity is 25.0 m/s directed at 40.0°
with the face of the cliff, as shown in the figure. The coin hits the ground 3.75 s after being thrown
and feels no appreciable air resistance as it falls.
25.0 m/s
Cliff
Ground
40.0

Expert Solution

Step 1

$G i v e n t h a t, A m a n t h r o w s a c o i n t h e e d g e o f a c l i f f I n i t i a l v e l o c i t y o f c o i n i s 25.0 m / s D i r e c t e d a t 40.0 ° C o i n h i t s t h e g r o u n d 3.75 s a f t e r b e i n g t h r o w n W e w i l l r e s o l v e t h e v e l o c i t y, U_{y} = 25 \cos 40 = 19.15 m / s (u p w a r d) U_{x} = 25 \sin 40 = 16.07 m / s (h o r i z o n t a l) w h e r e a s, h = U_{y} t + (\frac{1}{2} g t^{2}) = (19.15 m / s \times 3.75 s) + \frac{1}{2} \times 9.8 m s^{- 2} \times {(3.75 s)}^{2} = 140.71 m H o r i z o n t a l r a n g e, U_{x} t = 16.07 m / s \times 3.75 = 60.3 m$

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