A man stands on the lateral surface of a cylinder, moves his legs, and moves the cylinder with constant speed (see figure). Considering that the coefficient of friction between the shoes and the cylinder is mu = 0.3. What will be the friction force between the cylinder and the man. The mass of man m = 70 Kg.

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A: Write a given value of the question is, r=1.50m, μ=0.30 and g =9.81 m/s2

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A: Tension in the rope = weight of rope + weight of hanging box   = 50 N + 100 N   = 150N

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A:

Q: A skateboarder is attempting to make a circular arc of radius r = 19 m in a parking lot. The total…

A: mass = 95 kg coefficient of static friction = 0.66 radius (r) = 19 m

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Q: The light right-angle boom which supports the 450-kg cylinder is supported by three cables and a…

A: Solution:   The Reactions at O and cable tensions are calculated using below:

Q: amusement park there is a ride in which cylindrically shaped chambers spin around a central axis.…

A: We know that We have given that an amusement park there is a ride in which cylindrically shaped…

Q: 1.0m 3.0m 0.5m mi m, PA N, 5. The drawing above shows two objects on a board supported at two…

A: Given, M1 = 40 kg M2 = 20 kg M3 = 10 kg  We know g = 9.8 m/s2

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Q: A skateboarder is attempting to make a circular arc of radius r = 19 m in a parking lot. The total…

A: given,radius r = 19m. m = 87 kg. μs = 0.68The coefficient of kinetic friction is μk = 0.13

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A:

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Q: A skateboarder is attempting to make a circular arc of radius r = 16 m in a parking lot. The total…

A: given,   radius r = 16 m.  m = 91 kg.  μs = 0.69 . The coefficient of kinetic friction is μk = 0.24

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.