A magnetic circuit consists of two materials as shown in Fig. 3.48. The core has uniform cross-section of 6 cm². The core carries a winding with 900 turns. The current in the coil is 3 A. Calculate the flux produced in the air gap if the length of the air gap is 1mm. Relative permeability of material A is 1000 and that for B is 1500. The length of the magnetic circuit for A is 80 cm and for B it is 50 cm.

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Electrical magnetic circuit problem need correct solution 

A magnetic circuit consists of two materials as shown in Fig. 3.48. The
core has uniform cross-section of 6 cm². The core carries a winding with 900 turns. The
current in the coil is 3 A. Calculate the flux produced in the air gap if the length of the air
gap is 1mm. Relative permeability of material A is 1000 and that for B is 1500. The length
of the magnetic circuit for A is 80 cm and for B it is 50 cm.
a =6 cm²
Material A
A=80 cm
-Air gap
Material B
a=50 cm
2
a = 6 cm
Transcribed Image Text:A magnetic circuit consists of two materials as shown in Fig. 3.48. The core has uniform cross-section of 6 cm². The core carries a winding with 900 turns. The current in the coil is 3 A. Calculate the flux produced in the air gap if the length of the air gap is 1mm. Relative permeability of material A is 1000 and that for B is 1500. The length of the magnetic circuit for A is 80 cm and for B it is 50 cm. a =6 cm² Material A A=80 cm -Air gap Material B a=50 cm 2 a = 6 cm
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