A magazine reported that on average, American drivers will be involved in 3.4 car accidents while driving over their lifetime, with a standard deviation of 0.68. Number of accidents for American drivers follows a normal distribution. Four Americans who are no longer driving were randomly selected. What is the probability that their average number of accidents while driving will be larger than 4? P(E > 125) = %3D For this problem, we were told that the distrihution is normal If the -har the distrik utin

Q: Adult human body temperatures are normally distributed with a mean of 98 degrees F and a standard…

A: From the provided information,

Q: Empirical evidence shows that the "normal" resting adult body temperature is normally distributed…

A: Given that.   X~N( μ , ?)   μ=98.2 , ?=0.7   Z-score =( x - μ )/?

Q: Suppose the mean income of firms in the industry for a year is 100 million dollars with a standard…

A: Given,mean(μ)=100Standard deviation(σ)=15

Q: The patient recovery time from a particular surgical procedure is normally distributed with a mean…

A: Mean ()=5.7standard deviation ()=2.3

Q: The distribution of heart rates for women ages 20-39 is approximately normal with a mean of 73 beats…

A: The mean is 73 and the standard deviation is 15.9.sample size, n = 6.

Q: Tiger Woods hits an average driver 287.2 yards with a standard deviation of 24.6 yards. What is the…

A: The probability value is calculate by means of standard normal variate with the random variable,…

Q: Suppose that heights of 10-year-old boys in the US vary according to a normal distribution with mean…

A: The objective of this question is to find the probability that the height of a randomly selected…

Q: Scores on the Critical Reading part of the SAT exam in a recent year were roughly Normal with mean…

A:

Q: Scores on the Critical Reading part of the SAT exam in a recent year were roughly Normal with mean…

A: From the provided information, Mean (µ) = 496 Standard deviation (σ) = 115 X~N (496, 115) Sample…

Q: The mean age that cats get adopted at a shelter is 21.4 months with a standard deviation of 3.6…

A: Normal distribution is also known as the Gaussian distribution . It is widely used in statistics .

Q: the life expectancy for a species of certain insects is normally distributed with mean of 14.3…

A: It is given that the mean is 14.3 and the standard deviation is 4.3.

Q: Suppose the weight of hummingbirds are distributed normally with a mean of 25 oz and a standard…

A: Obtain the probability that a randomly selected hummingbird weighs more than 28oz. The probability…

Q: The length of an episode of the hit TV show, Fake Blood, is normally distributed with a mean of 62…

A: Given that  X~Normal(μ=62 , ?=4.5) Mean=μ=62 , Standard deviation=?=4.5)

Q: The weight of a certain type of dog is normally distributed with a mean of 34.7 pounds, and standard…

A:

Q: The time spent in days waiting for a heart transplant can be approximated by a normal distribution…

A: Given information- Population mean, μ = 127 days Population standard deviation, σ = 23.5 days Since…

Q: The mean age that cats get adopted at a shelter is 21.4 months with a standard deviation of 3.6…

A: Solution: Let X be the age. From the given information, X follows normal distribution with mean…

Q: annual precipitation amounts in a certain mountain range are normally distributed with a mean of 82…

A: Given,sample size(n)=25mean(μ)=82standard deviation(σ)=9

Q: Scores on the Critical Reading part of the SAT exam in a recent year were roughly Normal with mean…

A: The mean is 496 and the standard deviation is 115.

Q: A normal distribution has a mean 80 and standard deviation is 10. What is the probability of…

A: Given:    µ = 80     σ = 10

Q: Historically, the average score of PGA golfers for one round is 65 with a standard deviation of…

A: Answer:- Given , the average score of PGA golfers for one round is (µ) 65 with a standard deviation…

Q: Almost all medical schools require applicants to take the Medical College Admission Test (MCAT).…

A: Obtain the probability that this sample will have an average score between 23 and 26.   The…

Q: Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy…

A: From the provided information,Mean (µ) = 38Standard deviation (σ) = 12

Q: Suppose the mean income of firms in the industry for a year is 30 million dollars with a standard…

A:

Q: The mean amount purchased by each customer on non-medical mask at Chopper Drug Mart is 23 dollars…

A: From given,Mean = μ = 23Standard deviation = σ = 5Sample size = n = 50We have to find the…

Q: The mean weight of a sample of chocolate bars from a particular chocolate factory is 8 ounces with a…

A: Let X represent the random variable   Mean=8 SD=0.1   X~ Normal (8, 0.12)

Q: The final exam scores of students taking a statistics course are normally distributed with a…

A: Given information- Population mean, µ = 72 Population standard deviation, σ = 8 Let, X be the final…

Q: Suppose that heights of 10-year-old boys in the US vary according to a normal distribution with mean…

A: The objective of this question is to find the probability that the height of a randomly selected…

Q: Suppose the mean income of firms in the industry for a year is 100 million dollars with a standard…

A:

Q: The height of 10 year old females is normally distributed with a mean of 54.8 inches and a standard…

A: It is given that mean and standard deviation are 54.8 inches and 2.74 inches, respectively.

Q: The average rainfall in a certain area is 24.5 inches per year, with a standard deviation of 3…

A:

Q: The population average fuel efficiency of U.S. light vehicles for 2005 was 21 mpg. If the standard…

A: Given,sample size (n)=25sample mean(μ)=21standard deviation(σ)=2.9

Q: The Centers for Disease Control report that the total cholesterol levels for women, age 20-29, are…

A: Given, Mean = 183 Standard deviation = 37.2 Sample size = 30   The objective to is find the…

Q: According to data from the U.S. Army the average foot length of women as normally dis-tributed with…

A: It is given that the mean is 9.6 and the standard deviation is 0.5.

Q: Suppose the mean income of firms in the industry for a year is 25 million dollars with a standard…

A: Suppose the random variable x defines the income of firms in the industry.