A machinist turns the power on to a grinding wheel, which is at rest at time t-D0.00s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 3 rad/s^2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to 17 s 10s 8.3s 21s 23 s

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A machinist turns the power on to a grinding wheel, which is at rest at time t-D0.00s. The
wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s.
The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel
decelerates uniformly at 3 rad/s^2 until the wheel stops. In this situation, the time interval of
angular deceleration (slowing down) is closest to
17 s
10s
8.3s
21s
23 s
Transcribed Image Text:A machinist turns the power on to a grinding wheel, which is at rest at time t-D0.00s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 3 rad/s^2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to 17 s 10s 8.3s 21s 23 s
Expert Solution
Step 1

initial angular speed = 0 radsecfinal angular speed after 10 seconds (ω) = 25 radstime for which the machine is made to run at ω = 37 sec uniform deacceleration (α)= 3 rads2

 

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