A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter solution as an interval or union of intervals. help (intervals) In absolute value notation, where a represents the machined diameter, this is: A. x-5.5 ≤ 0.02 B. x -0.02 ≥ 5.5 OC. x - 5.5 ≥ 0.02 D. x -0.02 ≤ 5.5 E. None of the above

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals.

In absolute value notation, where \( x \) represents the machined diameter, this is:

- A. \( |x - 5.5| \leq 0.02 \)
- B. \( |x - 0.02| \geq 5.5 \)
- C. \( |x - 5.5| \geq 0.02 \)
- D. \( |x - 0.02| \leq 5.5 \)
- E. None of the above
Transcribed Image Text:A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals. In absolute value notation, where \( x \) represents the machined diameter, this is: - A. \( |x - 5.5| \leq 0.02 \) - B. \( |x - 0.02| \geq 5.5 \) - C. \( |x - 5.5| \geq 0.02 \) - D. \( |x - 0.02| \leq 5.5 \) - E. None of the above
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the correct diameter is 5.5 inches 

error=0.02

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Follow-up Question
**Problem Statement:**

A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals.

**Solution Approach:**

To find the acceptable range of diameters, calculate the interval within 0.02 inches of the target diameter (5.5 inches). This means the diameter can be up to 0.02 inches smaller or larger than 5.5 inches.

1. **Calculate the lower bound:**  
   5.5 inches - 0.02 inches = 5.48 inches

2. **Calculate the upper bound:**  
   5.5 inches + 0.02 inches = 5.52 inches

**Interval Notation:**

The possible diameters that will work can be represented as the interval:

\[ [5.48, 5.52] \]

This interval includes all diameters from 5.48 inches to 5.52 inches, inclusive.
Transcribed Image Text:**Problem Statement:** A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals. **Solution Approach:** To find the acceptable range of diameters, calculate the interval within 0.02 inches of the target diameter (5.5 inches). This means the diameter can be up to 0.02 inches smaller or larger than 5.5 inches. 1. **Calculate the lower bound:** 5.5 inches - 0.02 inches = 5.48 inches 2. **Calculate the upper bound:** 5.5 inches + 0.02 inches = 5.52 inches **Interval Notation:** The possible diameters that will work can be represented as the interval: \[ [5.48, 5.52] \] This interval includes all diameters from 5.48 inches to 5.52 inches, inclusive.
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