A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter solution as an interval or union of intervals. help (intervals) In absolute value notation, where a represents the machined diameter, this is: A. x-5.5 ≤ 0.02 B. x -0.02 ≥ 5.5 OC. x - 5.5 ≥ 0.02 D. x -0.02 ≤ 5.5 E. None of the above
A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter solution as an interval or union of intervals. help (intervals) In absolute value notation, where a represents the machined diameter, this is: A. x-5.5 ≤ 0.02 B. x -0.02 ≥ 5.5 OC. x - 5.5 ≥ 0.02 D. x -0.02 ≤ 5.5 E. None of the above
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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
Transcribed Image Text:A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals.
In absolute value notation, where \( x \) represents the machined diameter, this is:
- A. \( |x - 5.5| \leq 0.02 \)
- B. \( |x - 0.02| \geq 5.5 \)
- C. \( |x - 5.5| \geq 0.02 \)
- D. \( |x - 0.02| \leq 5.5 \)
- E. None of the above
Expert Solution

Step 1
Given,
the correct diameter is 5.5 inches
error=0.02
Step by step
Solved in 2 steps

Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question
![**Problem Statement:**
A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals.
**Solution Approach:**
To find the acceptable range of diameters, calculate the interval within 0.02 inches of the target diameter (5.5 inches). This means the diameter can be up to 0.02 inches smaller or larger than 5.5 inches.
1. **Calculate the lower bound:**
5.5 inches - 0.02 inches = 5.48 inches
2. **Calculate the upper bound:**
5.5 inches + 0.02 inches = 5.52 inches
**Interval Notation:**
The possible diameters that will work can be represented as the interval:
\[ [5.48, 5.52] \]
This interval includes all diameters from 5.48 inches to 5.52 inches, inclusive.](https://content.bartleby.com/qna-images/question/87c9e35a-c40b-4293-8ffa-6a1a5ded8456/e02c94ed-3738-45c2-a80e-3f2f8cdfaa18/vkkr7a6b_thumbnail.png)
Transcribed Image Text:**Problem Statement:**
A machinist must produce a bearing that is within 0.02 inches of the correct diameter of 5.5 inches. What are the possible diameters that will work? Enter the solution as an interval or union of intervals.
**Solution Approach:**
To find the acceptable range of diameters, calculate the interval within 0.02 inches of the target diameter (5.5 inches). This means the diameter can be up to 0.02 inches smaller or larger than 5.5 inches.
1. **Calculate the lower bound:**
5.5 inches - 0.02 inches = 5.48 inches
2. **Calculate the upper bound:**
5.5 inches + 0.02 inches = 5.52 inches
**Interval Notation:**
The possible diameters that will work can be represented as the interval:
\[ [5.48, 5.52] \]
This interval includes all diameters from 5.48 inches to 5.52 inches, inclusive.
Solution
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