A machine purchased for $36,000 is expected to have a useful life of 6 years and a salvage value of $6,000. Using the straight-line method, what is the monthly amortization amount for this machine?
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- the first cost of a machine is 50,000 and if has a depreciation of 4,500 per year. if the salvage value at the end of 10 years is 5000, the book value at the end of 5 years is?A machine has a first cost of P45000 with an interest rate of 10% annually.Expected salvage value after 8 years is P8000. Find the book value after 5years using sinking fund method.A new machine can be purchased for $50,000. Its expected useful life is seven years, with a salvage value of $5,000. Annual revenues will be $22,000 per year and annual expenses will be 8,000 per year, over the seven-year study period. If the MARR is 10%, determine whether the offer should e accepted. O a. Acceptable and its AW = $4257 O b. Not acceptable and its AW = $2,345 O. Acceptable, and its AW = $5067 O d. Not acceptable and its AW = -$3,281
- A company is considering two methods for obtaining a certain part on annual basis. Method A will involve purchasing a machine for $60K with a life of 5 years, a $3K salvage value and a fixed annual operating cost of $10K. Additionally, each part produced by the method will cost $10. Method B will involve purchasing the part from a subcontractor for $27 per part. At an interest rate of 10% per year, What is the number of parts (in x thousands) per year required for the two methods to break even ? A. 1480 B.1490 C. 1500 which is it and whyA piece of equipment has a first cost of $75000, a maximum useful life of 4 years, and a market (salvage) value described by the relation Sk = 60000 – 10500k, where k is the number of years since it was purchased. The AOC series is estimated using AOC = 30000 + 4500k. The interest rate is 9% per year. When should the company replace this asset?A machine will cost $30,000 to purchase. Annual operating and maintenance costs (O&M) will be $2000. The machine will save $10,000 per year in labor costs. The salvage value of the machine after 5 years will be $7000. Calculate the machine’s present worth for an interest rate of 10%.
- A machine which costs P100,000 when new has a lifetime of 15 years and a salvage value equal to 20% of its original cost. If interest rate is 10% compounded annually, what is the capital recovery of the machine?The initial cost of a new machine is $10,000. The annual operating cost is $1,000/yr for first 3 years, and then becomes $3,000/yr after that. The machine needs a major repair at the end of 5th year, which costs $5,000. The machine has 10 years useful life with salvage value of $4,000. Calculate EUAC for keeping the machine for 10 years. (i=10%/yr)One of two methods must be used to produce expansion anchors. Method A costs $75,000 initially and will have a $19,000 salvage value after 3 years. The operating cost with this method will be $23,000 per year. Method B will have a first cost of $110,000, an operating cost of $19,000 per year, and a $31,000 salvage value after its 3-year life. The interest rate for both the methods is 11%. Which method should be used on the basis of a present worth analysis? The present worth of method A is (about -117,000) and that of method B is (is not about -172,000)
- A flexible pavement construction project is proposed. The estimated service life is 20 years. The initial cost is estimated at $205,000, and it would have a salvage value of $34,000 at the end of its useful life. The yearly maintenance is estimated at $2,505. What would be the present worth of life-cycle costs? What will be the user cost savings annually to justify the pavement construction ? Use interest rate of 5%.One of two methods must be used to produce expansion anchors. Method A costs $80,000 initially and will have a $15,000 salvage value after 3 years. The operating cost with this method will be $30,000 per year. Method B will have a first cost of $120,000, an operating cost of $8000 per year, and a $40,000 salvage value after its 3-year life. At an interest rate of 12% per year, which method should be used on the basis of a present worth analysis? Also, write the two spreadsheet functions to perform the PW analysis.A machine costs $10,000, has a useful life of 7 years and a salvage value of $1000.00 at the end of the 7th year. If the interest rate is 9.8% compounded monthly, what is the equivalent uniform annual cost (EUAC) of this machine?