A machine purchased for $36,000 is expected to have a useful life of 6 years and a salvage value of $6,000. Using the straight-line method, what is the monthly amortization amount for this machine?
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- the first cost of a machine is 50,000 and if has a depreciation of 4,500 per year. if the salvage value at the end of 10 years is 5000, the book value at the end of 5 years is?A machine has a first cost of P45000 with an interest rate of 10% annually.Expected salvage value after 8 years is P8000. Find the book value after 5years using sinking fund method.You are required to investigate the following project: The initial Investment at n=0 is $100,000. The project life is 10 years. Estimated annual operating cost : 34,000. The required minimum return on the investment :14%. The salvage value 8,000. What is the minimum annual revenues that should be generated to make the project worthwhile? 97842 52758 81921 45716 O O O O
- A new machine can be purchased for $50,000. Its expected useful life is seven years, with a salvage value of $5,000. Annual revenues will be $22,000 per year and annual expenses will be 8,000 per year, over the seven-year study period. If the MARR is 10%, determine whether the offer should e accepted. O a. Acceptable and its AW = $4257 O b. Not acceptable and its AW = $2,345 O. Acceptable, and its AW = $5067 O d. Not acceptable and its AW = -$3,281A new machine requires an investment of $630,000 and will generate $100,000 in cash inflows for 7 years, at which time the salvage value of the machine will be $130,000. Using a discount rate of 10%, the net present value of the machine is $_________A company is considering two methods for obtaining a certain part on annual basis. Method A will involve purchasing a machine for $60K with a life of 5 years, a $3K salvage value and a fixed annual operating cost of $10K. Additionally, each part produced by the method will cost $10. Method B will involve purchasing the part from a subcontractor for $27 per part. At an interest rate of 10% per year, What is the number of parts (in x thousands) per year required for the two methods to break even ? A. 1480 B.1490 C. 1500 which is it and why
- A project will produce an operating cash flow of $7,500 a year for 8 years. The initial fixed asset investment in the project will be $35,000. The net aftertax salvage value is estimated at $3,500 and will be received during the last year of the project's life. What is the IRR?A piece of equipment has a first cost of $75000, a maximum useful life of 4 years, and a market (salvage) value described by the relation Sk = 60000 – 10500k, where k is the number of years since it was purchased. The AOC series is estimated using AOC = 30000 + 4500k. The interest rate is 9% per year. When should the company replace this asset?A machine will cost $30,000 to purchase. Annual operating and maintenance costs (O&M) will be $2000. The machine will save $10,000 per year in labor costs. The salvage value of the machine after 5 years will be $7000. Calculate the machine’s present worth for an interest rate of 10%.
- A machine which costs P100,000 when new has a lifetime of 15 years and a salvage value equal to 20% of its original cost. If interest rate is 10% compounded annually, what is the capital recovery of the machine?The initial cost of a new machine is $10,000. The annual operating cost is $1,000/yr for first 3 years, and then becomes $3,000/yr after that. The machine needs a major repair at the end of 5th year, which costs $5,000. The machine has 10 years useful life with salvage value of $4,000. Calculate EUAC for keeping the machine for 10 years. (i=10%/yr)One of two methods must be used to produce expansion anchors. Method A costs $75,000 initially and will have a $19,000 salvage value after 3 years. The operating cost with this method will be $23,000 per year. Method B will have a first cost of $110,000, an operating cost of $19,000 per year, and a $31,000 salvage value after its 3-year life. The interest rate for both the methods is 11%. Which method should be used on the basis of a present worth analysis? The present worth of method A is (about -117,000) and that of method B is (is not about -172,000)