A machine manufactures little cylinders with half-spheres of the same radius on top of them. If the height of the cylinder part is h and the radius is r the volume is V= pi *r^2 *h +(1/2) * (4/3)*pi *r^3 . The height is very 7 cm with a possible error of +/- 0.02 cm and the radius is 3 cm with a possible error of +/- 0.05 cm. Using the differentials technique we did in class, what is the approximate error of the volume? You need to use the product rule in the first term. Error in Volume is approximately = _________

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A: Follow the procedure given below.