A m=0.25kg mass is attached to end of a thin uniform rod of mass M =1.34kg and length L=3.33m which is positioned vertically. The rod is pivoted at point O that is L/4 away from its center. The system is released and allowed to fall. Determine the speed of mass m when it passes trough the lowest point (when the rod is completely vertical). Take g=9.81m/s 2 Irod- CM -ML2. and express your answer using one decimal place. m L/2 L L/4 pivot
A m=0.25kg mass is attached to end of a thin uniform rod of mass M =1.34kg and length L=3.33m which is positioned vertically. The rod is pivoted at point O that is L/4 away from its center. The system is released and allowed to fall. Determine the speed of mass m when it passes trough the lowest point (when the rod is completely vertical). Take g=9.81m/s 2 Irod- CM -ML2. and express your answer using one decimal place. m L/2 L L/4 pivot
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![A m=0.25kg mass is attached to end of a thin uniform rod of mass M =1.34kg and length L=3.33m which is positioned vertically. The rod is pivoted at point O that is
LI4 away from its center. The system is released and allowed to fall. Determine the speed of mass m when it passes trough the lowest point (when the rod is
completely vertical). Take g=9.81m/s 2 Irod_
5 ML and express your answer using one decimal place.
CM 12
m
L/2
L/4
pivot](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F04d698b5-083c-4adc-ad20-c7fdfe433486%2F684b689a-6595-4b31-838e-2211c0d1d771%2Ftz3glbg_processed.png&w=3840&q=75)
Transcribed Image Text:A m=0.25kg mass is attached to end of a thin uniform rod of mass M =1.34kg and length L=3.33m which is positioned vertically. The rod is pivoted at point O that is
LI4 away from its center. The system is released and allowed to fall. Determine the speed of mass m when it passes trough the lowest point (when the rod is
completely vertical). Take g=9.81m/s 2 Irod_
5 ML and express your answer using one decimal place.
CM 12
m
L/2
L/4
pivot
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