A m = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = mr²2. The ring has an initial speed of v= 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. O a) What is the angular velocity of the ring when it is on the horizontal surface? v=1m/s b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step. The ring has a larger mass m (same r and v) The ring is replaced with a solid disc (same m, r, and v) d) How would the maximum height change in each of the following situations? Put an X in the correct answer for each statement. There is no friction and the ring slides instead of rolling (same m, r, and v) Higher v=0 Lower Same height h

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WORK FOR A,B,C, is provided below just need help with D

G
С
viven
m=2ку
Я =015ш
Let
FOR
2.
V = LM/8
angulee violaciety at hosirvontal surface is w
V - t
ш
=
*
Мен+шя
05
to = 2 had/x
Vic 2018
2 минуя
speed at point of top
= Lux+(2x0-50)
2 M/S
+4
Э
Э
From
TEL
жди
жди
жди
ди
h
conservation of
= TE'
=
=
=
=
ћ ww2 + II ш
шv2.
2
=
ћ mv2 + + ms2 (x)
12m² + 1/2 √²
V2
–
С
у2
1²
9-8
сисаду
М
0.102 щ
и = 0-102 ш
ans
Transcribed Image Text:G С viven m=2ку Я =015ш Let FOR 2. V = LM/8 angulee violaciety at hosirvontal surface is w V - t ш = * Мен+шя 05 to = 2 had/x Vic 2018 2 минуя speed at point of top = Lux+(2x0-50) 2 M/S +4 Э Э From TEL жди жди жди ди h conservation of = TE' = = = = ћ ww2 + II ш шv2. 2 = ћ mv2 + + ms2 (x) 12m² + 1/2 √² V2 – С у2 1² 9-8 сисаду М 0.102 щ и = 0-102 ш ans
A m = 2kg ring has a radius of r = 0.5m. The moment of
inertia of a ring is I =mr².
The ring has an initial speed of v = 1 m/s on the
horizontal surface. It rolls, without slipping, along the
surface and up the ramp, where it stops when it
reaches a height h.
v=1m/s
a) What is the angular velocity of the ring when it is on the horizontal surface?
b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring?
c) Use Conservation of Energy to find the maximum height of the ring, h.
Show all your work. Solve the problem using variables.
Only substitute numbers in the very last step.
d) How would the maximum height change in each of the following situations?
Put an X in the correct answer for each statement.
The ring has a larger mass m
(same r and v)
The ring is replaced with a solid disc
(same m, r, and v)
There is no friction and the ring slides instead of rolling
(same m, r, and v)
Higher
v=0
Lower
Same height
h
Transcribed Image Text:A m = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I =mr². The ring has an initial speed of v = 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. v=1m/s a) What is the angular velocity of the ring when it is on the horizontal surface? b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step. d) How would the maximum height change in each of the following situations? Put an X in the correct answer for each statement. The ring has a larger mass m (same r and v) The ring is replaced with a solid disc (same m, r, and v) There is no friction and the ring slides instead of rolling (same m, r, and v) Higher v=0 Lower Same height h
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