A lunar module weighs 12 tons on the surface of the Earth. How much work is done in propelling the module from the surface of the moon to a height of 45 miles? Consider the radius of the moon to be 1100 miles (from the center of the moon) and its force of gravity to be one-sixth that of Earth. Step 1 1 The force of gravity on the moon is th of that on the Earth. 6. Thus, the weight of the module on the moon will be (21); = M 2 tons. Step 2 You know that the weight varies inversely as the square of the distance from the center of the moon. Let this distance be x. Therefore, considering the weight as a function of x, F(x) is as follows. (Where k is a proportionality constant). F(x) x F(x) = = k = 2.42 × 10

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A lunar module weighs 12 tons on the surface of the Earth. How much work is done in propelling the module
from the surface of the moon to a height of 45 miles? Consider the radius of the moon to be 1100 miles (from
the center of the moon) and its force of gravity to be one-sixth that of Earth.
Step 1
The force of gravity on the moon is
th of that on the Earth.
Thus, the weight of the module on the moon will be
w = (12) =
2 tons.
%3D
%3D
Step 2
You know that the weight varies inversely as the square of the distance from the center of the moon. Let this
distance be x. Therefore, considering the weight as a function of x, F(x) is as follows. (Where k is a
proportionality constant).
F(x) c
k
F(x) =
2 =
== k = 2.42 × 10
Submit
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Transcribed Image Text:A lunar module weighs 12 tons on the surface of the Earth. How much work is done in propelling the module from the surface of the moon to a height of 45 miles? Consider the radius of the moon to be 1100 miles (from the center of the moon) and its force of gravity to be one-sixth that of Earth. Step 1 The force of gravity on the moon is th of that on the Earth. Thus, the weight of the module on the moon will be w = (12) = 2 tons. %3D %3D Step 2 You know that the weight varies inversely as the square of the distance from the center of the moon. Let this distance be x. Therefore, considering the weight as a function of x, F(x) is as follows. (Where k is a proportionality constant). F(x) c k F(x) = 2 = == k = 2.42 × 10 Submit Skip (you cannot come back)
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