A loudspeaker creates sound by pushing air back and forth with a paper cone that is driven by a magnetic force on a wire coil at the base of the cone. (Figure 1) shows the details. The cone is attached to a coil of wire that sits in the gap between the poles of a circular magnet. The 0.20 TT magnetic field, which points radially outward from NN to SS, exerts a force on a current in the wire, moving the cone. The coil of wire that sits in this gap has a diameter of 5.0 cmcm, contains 20 turns of wire, and has a resistance of 8.0 N. The speaker is connected to an amplifier whose instantaneous output voltage of 8.0 VV creates a clockwise current in the coil as seen from above.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A loudspeaker creates sound by pushing air back and
forth with a paper cone that is driven by a magnetic
force on a wire coil at the base of the cone. (Figure 1)
shows the details. The cone is attached to a coil of wire
that sits in the gap between the poles of a circular
magnet. The 0.20 TT magnetic field, which points radially
outward from NN to SS, exerts a force on a current in the
wire, moving the cone. The coil of wire that sits in this
gap has a diameter of 5.0 cmcm, contains 20 turns of
wire, and has a resistance of 8.0 N. The speaker is
connected to an amplifier whose instantaneous output
voltage of 8.0 VV creates a clockwise current in the coil
as seen from above.
The answer is NOT F=0.39275 N
Transcribed Image Text:A loudspeaker creates sound by pushing air back and forth with a paper cone that is driven by a magnetic force on a wire coil at the base of the cone. (Figure 1) shows the details. The cone is attached to a coil of wire that sits in the gap between the poles of a circular magnet. The 0.20 TT magnetic field, which points radially outward from NN to SS, exerts a force on a current in the wire, moving the cone. The coil of wire that sits in this gap has a diameter of 5.0 cmcm, contains 20 turns of wire, and has a resistance of 8.0 N. The speaker is connected to an amplifier whose instantaneous output voltage of 8.0 VV creates a clockwise current in the coil as seen from above. The answer is NOT F=0.39275 N
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